(x-h)^2 + (y-k)^2 = r^2 where h & k are the x,y values of the center point
(x + 1)^2 + (y-3)^2 = 4^2
<span>(x + 1)^2 + (y-3)^2 = 16</span>
Answer:
yea by using a resipe
Step-by-step explanation:
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Answer/Step-by-step explanation:
✔️Using trigonometric ratio, find b:
Reference angle = 45
opposite = 8
Hypotenuse = b
Thus,
Sin(45) = 8/b
b = 8/sin(45)
b = 8/(1/√2) (sin 45 = 1/√2)
b = 8 × √2/1
b = 8√2
✔️Find a using trigonometric ratio:
Reference angle = 60°
Hypotenuse = b = 8√2
Adjacent = a
Therefore,
Cos(60) = a/8√2
8√2*cos(60) = a
8√2*½ = a
4√2 = a
a = 4√2
✔️Find c using Pythagorean Theorem:
c² = b² - a²
c² = (8√2)² - (4√2)²
c² = 128 - 32
c² = 96
c = √96
c = √(16*6)
c = 4√6