Ok, so...what is the question?...
Answer:
see below
Step-by-step explanation:
exponent to log: 
= c ---> logₐc = b
ie. question 6
log ₁₀(3x+1) = 2 -----> 
that will get you through questions 1 to 3, 5 to 6, and 8
in question 4, all you have to do is know that 2^2 = 4 and 2^3 = 8, by setting the bases equal, you can manipulate the exponents to get 2x+8 = 3x-3
for questions 7 and 9,
remember that:
logₐc + logₐd = logₐ(cd)
logₐc - logₐd = logₐ(
)
remember change of base is 
, this will be useful if you need your calculator since calculators only have base 10 and maybe if your calculator is good enough natural base e
Answer:
C and D
Step-by-step explanation:
5^3 - 5^0 = 125 - 1 = 124, so it's not A
5^12 / 5^4 = 5^(12-4) = 5^8, so it's not B
5^7 * 5^-4 = 5^(7+(-4)) = 5^3, so it can be C
5^0 * 5^3 = 5^(0+3) = 5^3, so it can be D
5 + 5^2 = 5 + 25 = 30, so it can't be E
First of all, just to avoid being snookered by a trick question, we should verify that these are really right triangles:
7² + 24² really is 25² , and 8² + 15² really is 17² , so we're OK there.
In the first one:
sin(one acute angle) = 7/25 = 0.28
the angle = sin⁻¹ (0.28) = 16.26°
the other acute angle = (90° - 16.26°) = 73.74°
In the second one:
sin(one acute angle) = 8/17 = 0.4706...
the angle = sin⁻¹ (0.4706...) = 28.07°
the other acute angle = (90° - 28.07°) = 61.93°
I'm sorry, but just now, I don't know how to do the
third triangle in the question.
Answer:
60?
Step-by-step explanation:
12*5=60
