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kotegsom [21]
3 years ago
9

A rectangular garden that measures 6 feet by 8 feet is roped off to form a right triangle. What is the length of the rope? A. 28

ft B. 5 ft C. 100 ft D. 10 ft
Mathematics
2 answers:
Katen [24]3 years ago
7 0

Answer:

Option D, 10 feet

Step-by-step explanation:

A rectangular garden that measures 6 feet by 8 feet. Garden is to be roped off to form a right angled triangle.

To make a right triangle rope should be tied diagonally.

Therefore, length of the rope = \sqrt{Length^{2}+width^{2}}

                                                = \sqrt{6^{2}+8^{2}}

                                                = \sqrt{36+64}

                                                = \sqrt{100}

                                                = 10 feet.

Option D 10 feet. is the answer.

ss7ja [257]3 years ago
3 0
Rope(r)
By using Pythagoras:
r^2 = 8^2 + 6^2
r^2 = 64 + 36
r^2 = 100
r = square root of 100
r = 100ft
The answer is C. 100ft
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Using Multiplication Property of Equality, multiply both sides by 2.

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Using Subtraction Property of Equality, subtract 6n from both sides.

7n-6n=6n+8-6n

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From the given options only one property is not used, i.e., Zero Product Property.

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Step-by-step explanation:

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iragen [17]

\bold{\huge{\orange{\underline{ Solution }}}}

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

  • \sf{ 2 , 14 ,.... 98 }
  • <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

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<u>Here</u><u>, </u>

Common difference of an AP

\sf{ a2 - a1 }

\sf{ = 14 - 2}

\sf{ = 12}

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

\sf{an = a1 + ( n - 1 )d}

\sf{a5 = 2 + ( 5 - 1 )12}

\sf{a5 = 2 + 4 × 12}

\sf{a5 = 2 + 48}

\sf{\red{a5 = 50}}

Hence, The 5th term of given AP is 50

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