A) 2^(x+3)= 4^(2x)
make base number the same
2^(x+3)= 2^2 (2x)
set the exponents equal to eachother
x+3=2 (2x)
x+3=4x
-x both sides
3=3x
÷3 both sides
x=1
b) 16^(1/5)×2^(x)=8^(3/4)
make base same number
2^4 (1/5)×2^(x)=2^3 (3/4)
2^(4/5)×2^(x)=2^(9/4)
set exponents
4/5 +x=9/4
-4/5 both sides
x= 29/20
Answer:
There are 
alternative schools in the country
Step-by-step explanation:
Let
x------> the number of charter schools
y-----> the number of alternative schools
we know that
-----> equation A
substitute the value of x in the equation A and solve for y
Answer:
Using Pythagorean theorem:
Diagonal = sqrt( 60^2 + 100^2) = 116.62
Hope this helps!
:)
<h3>Answer:</h3>
y = 28
<h3>Explanation:</h3>
The base angles of the isosceles triangle are congruent, so the sum of angles is ...
34° + 34° + 4y° = 180°
... 4y = 180 -68 . . . . . divide by °, subtract 68
... y = 112/4 = 28 . . . . divide by the coefficient of y
The value for y is 28.
_____
You have not asked about x in either figure.
<em>First figure</em>
Since the angles are congruent, the sides are congruent. Then ...
... 6x -3 = 5x
... x = 3 . . . . . . add 3-5x
<em>Second figure</em>
The base angles of the isosceles triangle are congruent, so
... 34° = (x -5)°
... 34+5 = x = 39 . . . . . . . divide by °, add 5.
Answer:
Step-by-step explanation:
y = -3x + 9 ⇌ 3x = 9 - y ⇌ x = -y/3 + 9/3 ⇌ x = -y/3 + 3
