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lana [24]
3 years ago
14

I have to find the perimeter and area for this figure how do I?

Mathematics
2 answers:
Mice21 [21]3 years ago
8 0
Perimeter add them all up. Area multiply
nikdorinn [45]3 years ago
4 0
Add the total then multiply
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Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ
dimaraw [331]

For this case we must simplify the following expression:

\frac {\frac {2a + 1} {10a-5}} {\frac {10a} {4a ^ 2-1}} =

We apply double C:

\frac {(4a ^ 2-1) (2a + 1)} {10a (10a-5)} =

We apply distributive property in the numerator and we take common factor 5 in the denominator:

\frac {8a ^ 3 + 4a ^ 2-2a-1} {10a (5 (2a-1))} =

We factor the numerator:

\frac {(2a + 1) ^ 2 (2a-1)} {10a (5 (2a-1))} =\\\frac {(2a + 1) ^ 2 (2a-1)} {50a (2a-1)} =

We simplify:

\frac {(2a + 1) ^ 2} {50a}

Answer:

\frac {(2a + 1) ^ 2} {50a}

Option D

7 0
3 years ago
Read 2 more answers
(8.3+6.3)^2-66.138 26.4-3-8.8
AveGali [126]
Exact form: (8.3+6.3)^2-66.138
Decimal Form: 147.022
I don't really think that this is the answer to what you're looking for but I do think you made an error on your question.
7 0
4 years ago
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Given f(x)=4x+5 and g(x)= x^2+x; find (f∘g)(-5)<br> Please show all steps thank you
Greeley [361]

Answer:

(f\circ g)(-5)=85

Step-by-step explanation:

We are given:

\displaystyle f(x)=4x+5\text{ and } g(x)=x^2+x

And we want to find:

(f\circ g)(-5)

This is equivalent to:

\displaystyle =f(g(-5))

So, we will evaluate g(-5) first, which yields:

\displaystyle g(-5)=(-5)^2+(-5)=25-5=20

So:

=f(g(-5))=f(20)

Then:

\displaystyle f(20)=4(20)+5=80+5=85

Therefore:

(f\circ g)(-5)=85

6 0
3 years ago
12a^2*b^4-36a^2*b+44abc
spayn [35]

Let's simplify step-by-step.

12a^2*b^4-36a^2*b+44abc=

There are no like terms.

Answer:

12a^2*b^4-36a^2*b+44abc=

5 0
3 years ago
a dental company has rolls of floss that are 1872 in long they want to put the distance in the yard on their label what is the d
statuscvo [17]
Copy and paste ur answer onto internet it will tell u
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