Answer:
See below in bold,.
Step-by-step explanation:
There are 30-17 = 13 boys in the class.
a. Prob(First is a boy ) = 13/30 and Prob( second is a boy = 12/29).
As these 2 events are independent:
Prob( 2 boys being picked) = 13/30 * 12/29 = 26/145 or 0.179 to the nearest thousandth.
b. By a similar method to a:
Prob ( 2 girls being picked) = 17/30 * 16/29 = 136/435 = 0.313 to the nearest thousandth.
c. Prob (First student is a boy and second is a girl) = 13/30 * 17/29 = 221/870.
Prob ( first student is a girl and second is a boy) = 17/30 * 13/29 = 221/870
These 2 events are not independent so they are added:
Prob( one of the students is a boy) = 2 (221/870 = 221/435 = 0.508 to the nearest thousandth.
B. 180cm3
You have to find length, width, and height of both objects.
For the first one multiply:
3 x 8 x 5 = 120
Then multiply:
2 x 5 x 6 = 60
Add them together:
120 + 60 = 180cm3
Answer:
The equation of the line that is perpendicular to the line that passes through the point (-4, 2) is y = -9·x/5 + 18
Step-by-step explanation:
The coordinates of the point of intersection of the two lines = (5, 9)
The coordinates of a point on one of the two lines, line 1 = (-4, 4)
The slope of a line perpendicular to another line with slope, m = -1/m
Therefore, we have;
The slope, m₁, of the line 1 with the known point = (9 - 4)/(5 - (-4)) = 5/9
Therefore, the slope, m₂, of the line 2 perpendicular to the line that passes through the point (-4, 4) = -9/5
The equation of the line 2 is given as follows;
y - 9 = -9/5×(x - 5)
y - 9 = -9·x/5 + 9
y = -9·x/5 + 9 + 9
y = -9·x/5 + 18
Therefore, the equation of the line that is perpendicular to the line that passes through the point (-4, 2) is y = -9·x/5 + 18.
Answer:
y=5
Step-by-step explanation:
b-intercept is the same as y-intercept
The correct answer is
In fact, this is a trinomial of the form
, whose solutions are given by
Using this formula for the trinomial of the problem, we find:
<span>we see that this trinomial has two coincident solutions (x=3 with multiplicity 2). This means that it can be rewritten as a perfect square, in the following form:
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