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scoundrel [369]
3 years ago
14

For the quadrant in which the following point is located, determine which of the functions are positive.

Mathematics
1 answer:
brilliants [131]3 years ago
3 0

Answer:

quadrant 1

Step-by-step explanation:

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Find the value of n so that the line perpendicular to y = (-1/3)X-4 passes through the points (n. 6) and (4,15).
iogann1982 [59]

Answer:

1

Step-by-step explanation:

The slope of the perpendicular is the negative inverse of the slope of the line.

m = -1 / (-⅓)

m = 3

The slope between the two points is 3, so:

3 = (15 − 6) / (4 − n)

3 (4 − n) = 9

4 − n = 3

n = 1

7 0
3 years ago
Translate each sentence into an equation.
mihalych1998 [28]

Answer:

1. 1/2x = 4

2. x - 6 = 9

3. 2x = 5x + 12

4. 2x + 5 = x - 5

5. 2x + 11 = x - 5

Hope this helps you!


3 0
3 years ago
What is the following simplified product? Assume
Yanka [14]

<u>Answer:</u>

The correct answer option is D. 10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}.

<u>Step-by-step explanation:</u>

We are given the following expression:

\left ( \sqrt { 10 x ^ 4 } -x \sqrt { 5 x ^ 2 } \right ) \left ( 2 \sqrt { 15 x ^ 4 } + \sqrt { 3 x ^ 3 } \right )

Assuming that x\geq 0, we are to find its simplified product.

\left ( \sqrt { 10 x ^ 4 } -x \sqrt { 5 x ^ 2 } \right ) \left ( 2 \sqrt { 15 x ^ 4 } + \sqrt { 3 x ^ 3 } \right )

\\\\ = 2 \sqrt { 150 x ^ 8 } + \sqrt { 3 0 x ^ 7 }-2x\sqrt{75x^6}-x\sqrt{15x^5} \\\\ =2\sqrt{25\times6x^8}+x^3\sqrt{30x}-2x\sqrt{25\times3x^6}-x^3\sqrt{15x} \\\\ =10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}

4 0
3 years ago
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eimsori [14]

Euler's formula for Vertices, Edges and faces is V-E+F = 2

Replace the letters with the given information and solve for the missing one.

From the problem V ( Vertices) = 11 and F (faces) = 15.

11 - E + 15 = 2

11 + 15 = 26

26 - E = 2

E = 26-2

E = 24

The answer is b. 24

7 0
3 years ago
If John worked 6 hours a day for 30 days with an hourly rate of 25$ how much did he earn the entire 30 days?
morpeh [17]

John would make <em>4,500$</em> for the 30 days he worked 25$ for 6 hours.

6 0
3 years ago
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