Answer:
Step-by-step explanation:
Since the time required to finish a test is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - u)/s
Where
x = required to finish a test
u = mean time
s = standard deviation
From the information given,
u = 60 minutes
s = 10 minutes
We want to find the probability that a student will finish the test between 50 and 60 minutes. It is expressed as
P(50 ≤ x ≤ 60)
For x = 50
z = (50 - 60)/10 = - 1
Looking at the normal distribution table, the probability corresponding to the z score is 0.1587
For x = 60
z = (60 - 60)/10 = 0
Looking at the normal distribution table, the probability corresponding to the z score is 0.5
Therefore,
P(50 ≤ x ≤ 60) = 0.5 - 0.1587 = 0.3413
