The perimeter of an isosceles triangle is 62 cm. the equal sides are four less than the base. determine the length of each side

Question

lubasha [3.4K]

3 years ago

14

The perimeter of an isosceles triangle is 62 cm. the equal sides are four less than the base. determine the length of each side

of the triangle

Mathematics

2 answers:

Len [333] · Answer 1 · 2022-03-27T18:17:22+03:00

Len [333]3 years ago

7 0

X + 2(x - 4) = 62
x + 2x - 8 = 62
3x - 8 = 62
3x = 70
x = 23 1/3 cm

malfutka [58] · Answer 2 · 2022-03-27T20:31:49+03:00

To start, keep in mind that every isosceles triangle has two sides that are equal, and given that the equal sides are 4 less than the base, let the base be represented as the value of x and the two equal sides be represented by the expression x-4.

Then, since perimeter is the sum of all the sides, and you already know your perimeter is 62 cm, you can set up an equation that looks like this:
x+(x-4)+(x-4)=62

Then, when you combine your like terms:
3x-8=62

Add -8 to both sides:
3x=70

And you get that the value of x or the base is 70/3.

Then, since you must find the lengths of the two equal sides, subtract 4 from 70/3 and you get that the two equal sides are 58/3 cm. Then, convert the improper fraction to a mixed fraction to get your answer as:

The lengths of the triangles are 23 1/3 by 19 1/3 by 19 1/3 cm