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mixer [17]
3 years ago
8

Which of the operating systems listed below was the last to be released

Computers and Technology
1 answer:
Elena-2011 [213]3 years ago
8 0

Mac OS came out in 2001. This is software that was created by Apple to run the "Mac Computers." This software is still used to this day.

MS-DOS came out in 1981. This is software that was created by Microsoft to run x86 computers. This software is no longer used.

Windows New Technology came out in 1985. This is software that was created by Microsoft to run a ton of different computers. This software is still used to this day.

Windows Vista came out in 2006. This software that was created by Microsoft to run a variety of personal computers. This software is no longer used.

By the information given, Windows Vista was the last to be released.

Best of Luck!

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5 0
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Jim is in the market for a car that will last for the next 10 years and has saved up some money for the purpose of a car. What’s
Ratling [72]
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8 0
3 years ago
Write a program that accepts a phrase of unspecified length on the command line. For example: prompt% letter print Operating Sys
Sedaia [141]

Answer:

Check the explanation

Explanation:

#define _MULTI_THREADED

#include <pthread.h>

#include <stdio.h>

#include <errno.h>

#define           THREADS          2

int               i=1,j,k,l;

int argcG;

char *argvG[1000];

void *threadfunc(void *parm)

{

int *num;

num=(int*)parm;

while(1)

   {

   if(i>=argcG)

   break;

   if(*num ==1)

   if(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u')

   {

   printf("%s\n",argvG[i]);

   i++;

   continue;

   }

    if(*num ==2)

   if(!(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u'))

   {

   printf("%s\n",argvG[i]);

   i++;

   continue;

   }

   sched_yield();

   }

return NULL;

}

int main(int argc, char *argv[])

{

pthread_t            threadid[THREADS];

int                  rc=0;

int                  loop=0;

int arr[2]={1,2};

argcG=argc;

for(rc=0;rc<argc;rc++)

argvG[rc]=argv[rc];

printf("Creating %d threads\n", THREADS);

for (loop=0; loop<THREADS; ++loop) {

     rc =pthread_create(&threadid[loop], NULL, threadfunc,&arr[loop]);

}

for (loop=0; loop<THREADS; ++loop) {

   rc = pthread_join(threadid[loop], NULL);

}

printf("Main completed\n");

return 0;

}

The below attached image is a sample output

3 0
3 years ago
Look at the code below. What does it do?
yulyashka [42]

Answer:

3- The code takes in an input, turns it into an integer and then multiplies it by 2 and prints it

Explanation:

Look- First, the code snippet asks for an input (int or float) as "Rawheight".

Aftewards, it converts the input into an integer numeral(if it was a float) and multiplies it by 2.

This processed value is, then, further transferred to the variable "double_height" and is thereafter rendered on the user's virtual screen.

5 0
2 years ago
create your own min function that finds the minimum element in a list and use it in a separate function
schepotkina [342]

Answer:

def minfunction(mylist):

   min = mylist[0]

   for i in mylist:

       if i < min:

           min = i

   print("The minimum is: "+str(min))

   

def anotherfunction():

   mylist = []

   n = int(input("Length of list: "))

   for i in range(n):

       listelement = int(input(": "))

       mylist.append(listelement)

   minfunction(mylist)

   

anotherfunction()

Explanation:

This solution is implemented in Python

This defines the min function

def minfunction(mylist):

This initializes the minimum element to the first index element

   min = mylist[0]

This iterates through the list

   for i in mylist:

This checks for the minimum

       if i < min:

... and assigns the minimum to variable min

           min = i

This prints the minimum element

   print("The minimum is: "+str(min))

   

This defines a separate function. This  separate function is used to input items into the list

def anotherfunction():

This defines an empty list

   mylist = []

This prompts user for length of list

   n = int(input("Length of list: "))

The following iteration inputs elements into the list

<em>    for i in range(n):</em>

<em>        listelement = int(input(": "))</em>

<em>        mylist.append(listelement)</em>

This calls the minimum function

   minfunction(mylist)

   

The main starts here and this calls the separate function

anotherfunction()

5 0
3 years ago
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