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telo118 [61]
3 years ago
5

Salvatore attends class every 4 weeks, chess club every 2 weeks, and fencing lessons every 3 weeks. If he attended all three thi

s week, when will he attend all three again?
Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
6 0

Answer:

12

Step-by-step explanation:

Listing the weeks he will attend each item

Class  4,8,12,16

Chess 2,4,6,8,10,12

Fencing 3,6,9,12

Starting today at week 0, he will attend all 3 again at week 12

son4ous [18]3 years ago
6 0

Answer:

12 weeks

Step-by-step explanation:

We know that Salvatore attends class every 4 week, chess club every 2 weeks, and fencing lessons every 3 weeks.

If he attended all today, to find out when he will attend all again,we just need to find the least common multiple (LCM) of 3, 4, and 2.

The LCM of 3, 4, and 2 is 12.

So, he will attend all classes again after 12 weeks.

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10x + .0085x = 280000
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Answer:

x = 27976.22021

Step-by-step explanation:

10x + .0085x = 280000

Combine like terms

10.0085x = 280000

Divide by 10.0085 on each side

10.0085x /10.0085= 280000/10.0085

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3 years ago
Find the equation of a line containing the given point and slope (10,5); m=9/20
ohaa [14]
\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 10}}\quad ,&{{ 5}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{9}{20}
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-5=\cfrac{9}{20}(x-10)\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-5=\cfrac{9}{20}x-\cfrac{9}{2}\implies y=\cfrac{9}{20}x-\cfrac{9}{2}+5\implies y=\cfrac{9}{2}x+\cfrac{1}{2}
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3 years ago
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Step-by-step explanation:

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(x-a)^2+(y-b)^2=r^2

where:

  • (a, b) is the center
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From inspection of the diagram, the center of the circle <em>appears</em> to be at point (-3, 2), although this is not very clear.  Therefore, a = -3  and  b = 2.

Substitute these values into the general form of the equation of a circle:

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Therefore, the final equation of the given circle is:

\implies (x+3)^2+(y-2)^2=9

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Answer:

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