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3 years ago

What is the value of x

Mathematics

2 answers:

Goshia [24]3 years ago

4 0

the answer is C hope this helps

juin [17]3 years ago

4 0

Answer:

Value of y = 40°

Right option is C . 40°

Step-by-step explanation:

We have given a triangle

Three angle of triangle given as 2y , y+10° and 50°.

Angle sum of triangle is 180°

i.e 2y + ( y + 10°) + 50° = 180°

or 3y + 60° = 180°

or 3y = 180° - 60°

or 3y = 120°

or y = 40°

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salantis [7]

I hope it helps liked it and make it brainliest

so the answer is:y=sin (∅)

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2 years ago

6. Which of the following is the representation of a decimal number?

Ket [755]

Answer: I would say C, hope this helps

Step-by-step explanation:

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3 years ago

Painting. Quentin can paint the turret on a Queen Anne house in 40 hr. It takes Austin 50 hr to paint the same turret. How long

Lelechka [254]

Answer:

The answer to your question is 22.2 hours

Step-by-step explanation:

Data

Quentin 40 hr to paint a turret

Austin 50 hr to paint a turret

Use proportions to solve this problem

Quentin 1 turret ---------------- 40 hr Austin 1 turret --------------- 50 hr

x ---------------- 1 hr x ---------------- 1 hr

x = 0.025 turret x = 0.02 turret

Then

- In 1 hour they paint 0.025 + 0.02 = 0.045 of the turret

- In 10 hours they paint (10 x 0.025 + 10 x 0.02) = 0.25 + .2 = 0.45

- In 20 hours they paint (20 x 0.025 + 20 x 0.02) = 0.5 + 0.4 = 0.9

- In 22 hours they paint (22 x 0.025 + 22 x 0.02) = 0.55 + 0.44 = 0.99

- In 22.2 hours they paint (22.2 x 0.025 + 22.2 x 0.02) = 0.555 + .0.444 =

0.999

They paint the turret together in 22.2 hours

3 0

3 years ago

Need help. Please help.A,B,C Or D

Elenna [48]

B is the correct answer i think but i'm not a mathematician

8 0

3 years ago

17. A rectangular garden 200 square feet in area is to be fenced o against rabbits. Find thedimensions that will require the lea

torisob [31]

Answer:

$x=10$ feet and $y=20$ feet

The least amount of fencing required = 40 feet.

Step-by-step explanation:

Let us take $x$ be the length of the garden and $y$ be width of the garden.

The area of the rectangular garden will be, $A=x y=200$ ...{1}

Perimeter of the garden, $P=2 x+y$ .

[ because one side of the garden is protected by a barn ]

Thus,

$P=2 x+y$

$P=2 x+\frac{200}{x}$ [using 1]

$\frac{d P}{d x}=2-\frac{200}{x^{2}}$

For points of maxima or minima

$\frac{d P}{d x}=0 \Rightarrow 2-\frac{200}{x^{2}}=0 \Rightarrow x^{2}=100 \Rightarrow x=\pm 10$

Since length cannot be negative, $x=-10$ is rejected.

Thus,

$\frac{d^{2} P}{d x^{2}}=-(-2) \frac{200}{x^{3}}=\frac{400}{x^{3}}$

$\left(\frac{d^{2} P}{d x^{2}}\right)_{x=10}=\frac{400}{10^{3}}>0$

Hence at $x=10,$ , The perimeter $(P)$ will be min.

On substituting $x=10$ in $x y=200,$ then $y=20$

Hence, the dimensions of the garden are:

$x=10$ feet and $y=20$ feet

The perimeter, $P=20+20=40$ feet i.e the least amount of fencing required.

3 0

3 years ago