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Firlakuza [10]
3 years ago
13

Two positive charges enter the field (B = 0.500 T) below from the left, and a negative charge enters it from the right; they all

have identical speeds of 25.0 E6 m/s. The negative charge has the same mass as one of the positive charges, but the other positive charge is much more massive than the others.
A. True
B. False
Physics
1 answer:
rjkz [21]3 years ago
5 0

Answer:

the true claims

Explanation:

Electric charges obey Newton's second law

        F = m a

where the acceleration is centripetal and the force is magnetic

       F = q v x B

       a = v² / r

we substitute

    q v x B = m a

Suppose the magnetic field is perpendicular to the velocity, so the modulus of the vector product is

      q v B = m v² / r

       r = mv / qB

We see that the radius of the orbit depends on the mass, so if one of the particles has a greater mass, the radius of its orbit is greater and those of the same mass have identical radii of orbit.

 

therefore the radius of the negative particle must be equal to that of a positive charge and the other positive charge must have a much greater radius

the true claims

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Answer:

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7 0
3 years ago
1) Use SolidWorks (SW) FEA to apply a bending load of 600 lbf on the right end of the stepped shaft as shown below. This is the
salantis [7]

Solution :

Given :

L = 1 in

d = 0.75 in

D = 1 in

Fillet radius, r = 0.063 in

$K_{t_{bending}=\frac{\sigma_{FEA_{bending }}}{\sigma_{Nominal_{bending }}}$

We know that :

$\sigma_{b} = \frac{32M}{\pi d^3}$

$\sigma_{b} = \frac{32 \times (2998.63 \times 25.4)}{\pi (0.75 \times 25.4)^3}$

    $=112.27 \ N/mm^2$

$\sigma_{FEA} = 1.3 \times 10^8 \ N/m^2$

         $=1.3 \times 10^8 \times 10^{-6}$

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$k_t=\frac{130}{112.27}$

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8 0
3 years ago
In a certain process, the energy of the system decreases by 250 kJkJ. The process involves 480 kJkJ of work done on the system.
BigorU [14]

Answer:

-730KJ

Explanation:

According to the first law of thermodynamics;

Let the total energy of the system be ∆E

Let heat be q and let work the w

Since the energy decreases ∆E is negative

Since work is done on the system w= positive

So;

- 250 = 480 + q

q = -250 - 480

q=-730KJ

5 0
3 years ago
The gravity of Earth is attracting a person towards the center with 500N of gravitational force. The person is exerting a reacti
slavikrds [6]

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8 0
3 years ago
How are the electric field lines around a positive charge affected when a second positive charge is near it?
Lesechka [4]

Answer: The field lines bend away from the second positive charge

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4 0
4 years ago
Read 2 more answers
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