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kondor19780726 [428]
3 years ago
15

When one object pushes or pulls another object, the first object is________________________ a force on the second object.

Physics
1 answer:
Arlecino [84]3 years ago
5 0
The answer is inertia
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Write a short narrative from the perspective of a mineral moving through the rock cycle. The mineral must undergo at least four
Art [367]

Answer: Mineral and non- mineral components circulate in the environment in different forms whether it is in the form of solid, liquid, or gas.

Explanation:

Plants take up the minerals like calcium, potassium, nitrogen, sulphur, and others from the soil and utilize them for their survival and growth. These minerals are stored in the flowers, leaves, roots, and other plant parts and these plant parts are consumed by humans and animals. So, inorganic minerals from the soil are converted into organic forms by the plants again the minerals are decomposed into inorganic forms after the death of organisms and again mineral is converted into inorganic form in the soil and these minerals can become the component of the rocks after the sedimentation of the soil.

3 0
3 years ago
Determine Force. 589J of work was accomplished over a distance of 1100m, how much force was exerted? Include the correct units.
LiRa [457]

Answer:

Explanation:

Given:

A = 589 J

D = 1 100 m

____________

F - ?

A = F·D

F = A / D = 589 / 1100 ≈ 0.54 N

5 0
1 year ago
A 1500-W heater is connected to a 120-V line. How much heat energy does it produce in 2.0 hours? Hint: how are power and energy
ELEN [110]
Power is the rate of work done or produced by a system. It will have units of Watts which is equivalent to Joules per second. To determine the work or energy produced by the system, we multiply power with time. We do as follows:

Energy = Power x time
Energy = 1500 J/s (2.0 hr) (3600 s / 1 hr) 
Energy = 10800000 J
3 0
3 years ago
at what position an object be placed in front of a concave mirror of radius of curvature 40cm so that an erect image of magnific
Thepotemich [5.8K]
  • C=40cm
  • f=C/2=40/2=20

  • m=3

\\ \sf\longmapsto m=\dfrac{f}{f-u}

\\ \sf\longmapsto 3=\dfrac{20}{20-u}

\\ \sf\longmapsto 3(20-u)=20

\\ \sf\longmapsto 60-3u=20

\\ \sf\longmapsto 3u=40

\\ \sf\longmapsto u=13.3cm

  • m=magnification
  • f is focal length
  • C is radius of curvature
  • u is object distance
8 0
3 years ago
A 45.0-kg girl is standing on a 168-kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat,
muminat

Answer:

The speed of the plank relative to the ice is:

v_{p}=-0.33\: m/s

Explanation:

Here we can use momentum conservation. Do not forget it is relative to the ice.

m_{g}v_{g}+m_{p}v_{p}=0 (1)

Where:

  • m(g) is the mass of the girl
  • m(p) is the mass of the plank
  • v(g) is the speed of the girl
  • v(p) is the speed of the plank

Now, as we have relative velocities, we have:

v_{g/b}=v_{g}-v_{p}=1.55 \: m/s (2)

v(g/b) is the speed of the girl relative to the plank

Solving the system of equations (1) and (2)

45v_{g}+168v_{p}=0

v_{g}-v_{p}=1.55

v_{p}=-0.33\: m/s

I hope it helps you!      

8 0
3 years ago
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