All categories

3 years ago

When one object pushes or pulls another object, the first object is________________________ a force on the second object.

Physics

1 answer:

Arlecino [84]3 years ago

5 0

The answer is inertia

You might be interested in

A density triangle is a tool that can be used to find

Anna [14]

The answer is D
Hope this helps

4 0

3 years ago

It's nighttime, and you ve dropped your goggles into a 3.2-m-deep swimming pool. If you hold a laser pointer 0.90 m above the ed

yanalaym [24]

Answer:

The distance of the goggle from the edge is 5.30 m

Explanation:

Given:

The depth of pool (d) = 3.2 m

let 'i' be the angle of incidence

thus,

i = $tan^{-1}(\frac{2.2}{0.90})$

i = 67.75°

Now, Using snell's law, we have,

n₁ × sin(i) = n₂ × 2 × sin(r)

where,

r is the angle of refraction

n₁ is the refractive index of medium 1 = 1 for air

n₂ is the refractive index of medium 1 = 1.33 for water

now,

1 × sin 67.75° = 1.33 × sin(r)

r = 44.09°

Now,

the distance of googles = 2.2 + d×tan(r) = 2.2 + (3.2 × tan(44.09°) = 5.30 m

Hence, <u>the distance of the goggle from the edge is 5.30 m</u>

5 0

3 years ago

The pattern of weather in an area overtime is called

zzz [600]

The pattern of the temperature in a region day by day is called weather. The year by year temperature is a called climate.

6 0

3 years ago

A circular loop ( radius = 0.5 m) carries a current of 3.0 A and has unit normal vector of (2i - j +2k)/3 what is x component of

Roman55 [17]

Answer:

$T=9.42Nm$

Explanation:

From the question we are told that:

Radius $r= 0.5 m$

Current $I= 3.0 A$

Normal vector $n=\frac{(2i - j +2k)}{3}$

Magnetic field $B= (2i-6j) T$

Generally the equation for Area is mathematically given by

$A=\pi r^2$

$A=3.1415 *0.5^2$

$A=0.7853 m^2$

Generally the equation for Torque is mathematically given by

$T=A(i'*B)$

Where

$i'*B= \begin{bmatrix}2&-1&2\\2&-6&0\end{bmatrix}$

$X\ component\ of\ i'*B= [(-1 * 0)-(2*-6)]$

$X\ component\ of\ i'*B=12$

Therefore

$T=0.7853*12$

$T=9.42Nm$

7 0

3 years ago

You're using a monochromatic beam of light with wavelength 500 nm in an interferometer. What is the miminum distance you would n

Marina CMI [18]

Answer:

Minimum distance needed to move one of the mirrors = 125 nm

Explanation:

Constructive interference occurs when the maxima (trough or crest) of two waves that are in phase add together so that the amplitude of the resulting wave is equal to the sum of the individual amplitudes.

Destructive interference occurs when the maxima (trough or crest) of two waves that are out of phase by 180⁰ or half a wavelength combine to produce a smaller amplitude than the individual amplitudes that combine. It can even produce a wave of zero amplitude.

Since the spot of constructive interference has been changed to destructive interference, Path difference = Wavelength/2

Path difference = 500nm/2 = 250 nm

Path difference = 250 * 10⁻⁹ m

Since there are two interferometer's mirrors and only one is moved, the minimum distance will be a half of the path difference.

That is, minimum distance = (path difference)/2

Minimum distance = (250 * 10⁻⁹)/2

Minimum distance = 125 * 10⁻⁹ m

Minimum distance = 125 nm

5 0

3 years ago