5.6 x 2.1 x 6.6 = 77.616 2 significant figures would be 78 cm³ 2 decimal places would be 77.62 cm³
Answer:
3872/(x^2 - 2)
Step-by-step explanation:
Simplify the following:
(16^3 - 3^2 - 5×43)/(x^2 - 2)
3^2 = 9:
(16^3 - 9 - 5×43)/(x^2 - 2)
16^3 = 16×16^2:
(16×16^2 - 9 - 5×43)/(x^2 - 2)
| 1 | 6
× | 1 | 6
| 9 | 6
1 | 6 | 0
2 | 5 | 6:
(16×256 - 9 - 5×43)/(x^2 - 2)
16×256 = 4096:
(4096 - 9 - 5×43)/(x^2 - 2)
43 (-5) = -215:
(4096 - 9 + -215)/(x^2 - 2)
4096 - 9 - 215 = 3872:
Answer: 3872/(x^2 - 2)
Px + 12 = 17
px = 5
x = 5/p
ans) D
A. 38
Let X = seventh graders
6th graders are twice the number of 7th graders; therefore, 6th graders will be 2X.
The total number of students is 57.
2X + X = 57
3X = 57
X = 57 / 3
X = 19
IF X represents the 7th graders; there are 19 seventh graders present.
Since 6th graders are represented by 2X; Then, 2 * 19 = 38 is the number of 6th graders present.
Add both numbers to check: 19 + 38 = 57.
Let the two integers be x and x+1
(x+1)^2-x^2=21
x^2+2x+1-x^2=21
2x+1=21
2x=20
x=10
then x=10, x+1
10+1=11
the two integers are 10, 11
