Answer:
y = -2(x+2)(x-1)/((x+3)(x-6)) = (-2x^2 -2x +4)/(x^2 -3x -18)
Step-by-step explanation:
A polynomial function will have a zero at x=a if it has a factor of (x-a). For the rational function to have zeros at x=-2 and x=1, the numerator factors must include (x+2) and (x-1).
For the function to have vertical asymptotes at x=-3 and x=6, the denominator of the rational function must have zeros there. That is, the denominator must have factors (x+3) and (x-6). Then the function with the required zeros and vertical asymtotes must look like ...
f(x) = (x+2)(x-1)/((x+3)(x-6))
This function will have a horizontal asymptote at x=1 because the numerator and denominator degrees are the same. In order for the horizontal asymptote to be -2, we must multiply this function by -2.
The rational function may be ...
y = -2(x +2)(x -1)/((x +3)(x -6))
If you want the factors multiplied out, this becomes
y = (-2x^2 -2x +4)/(x^2 -3x -18)
You’re answer should be m= -2
In form
ax+by=c
slope=-a/b
y intercpept=c/b
so
-3x-4y=-12
a=-3
b=-4
c=-12
slope=-(-3)/-4=3/-4=-3/4
yint=-12/-4=3
slope=-3/4
yint is 3
Answer:
15
Step-by-step explanation:
3a+9=54
-9 -9
3a=45
:3 :3
a=15
Step-by-step explanation:
from,
An = 4n -13
A1 = 4 (1) - 13
> A1 = -9
A2 = 4(2) - 13
> A2 = -5
A3 = 4(3) - 13
> A3 = -1
A4 = 4(4) - 13
> A4 = 3