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vova2212 [387]
3 years ago
14

If a car travels 160 miles in 8 hours, what is the car’s speed?

Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0
Speed = Distance/Time = 160/8 = 20 miles/hour
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Help with this geometry question.
KATRIN_1 [288]

Plug in 4m in the space

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Which of the following lists of network types appears in decreasing order of size?
Tju [1.3M]

WAN, LAN, PAN

Wide Area Network, Local Area Network, Personal Area Network

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decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. −b b2 − 4ac 2a u
Romashka [77]

Answer:

Step-by-step explanation:

A quadratic equation can be factorised if and only if there are rational roots.

For any quadratic equation the discriminant decides about the nature of roots.

Thus only if the discriminant is a perfect square we can have rational roots and in this case only factorization is possible.

In the given equation

2x^2+ 7x+ 3 = 0\\a=2, b=7, c=3\\b^2-4ac = 1

Since 1 is a perfect square we can factor and solve

2x^2 +7x +3 = 0\\(2x+1)(x+3)=0\\x=-1/2 or x = -3

4 0
3 years ago
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A scuba diving company currently charges $100per dive. On average, there are 30 customers per day. The company performed a study
Semenov [28]

A. Total Revenue (R) is equal to price per dive (P) multiplied by number of customers (C). We can write R=PC.

Per price increase is $20. So four price increase is $20*4=$80. Hence, price per dive is 100+80=$180.

Also per price increase, 2 customers are reduced from 30. For 4 price increases, 4*2=8 customers are reduced. Hence, total customers is 30-8=22.

So Total Revenue is:

R=180*22=3960


B. Each price increase is 20. So x price increase is 20x. Hence, new price per dive would be equal to the sum of 100 and 20x.

Also per price increase, customers decrease by 2. So per x price increases, the customer decrease is 2x. Hence, new number of customers is the difference of 30 and 2x.

Therefor we can write the quadratic equation for total revenue as the new price times the new number of customers.

R=(100+2x)(30-2x)=-40x^{2}+400x+3000


C. We are looking for the point (x) at which the equation modeled in part (B) gives a maximum value of revenue (y). That x value is given as x=-\frac{b}{2a}, where a is the coefficient of x^{2} and b is the coefficient of x. So we have,

x=-\frac{b}{2a}=- \frac{400}{(2)(-40)}=5

That means, the greatest revenue is achieved after 5 price increases. Each price increase was 20, so 5 price increase would be 5*20=100. So the price that gives the greatest revenue is 100+100=200.

ANSWERS:

A. $3960

B. R=-40x^{2}+400x+3000

C. $200

4 0
3 years ago
Choose the graph that solve the following system x-4y=2 3x+2y=6
Elanso [62]
X - 4y = 2.....multiply by -3
3x + 2y = 6
-------------
-3x + 12y = -6 (result of multiplying by -3)
3x + 2y = 6
------------add
14y = 0
y = 0

3x + 2y = 6
3x + 2(0) = 6
3x = 6
x = 6/3
x = 2

solution is (2,0).....so the graph that has the two lines intersecting (crossing) at (2,0) is gonna be ur graph
5 0
3 years ago
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