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vova2212 [387]
3 years ago
14

If a car travels 160 miles in 8 hours, what is the car’s speed?

Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0
Speed = Distance/Time = 160/8 = 20 miles/hour
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Natalie is buying potatoes at the grocery store. If she buys 6 potatoes that each have a mass of 375 grams, what is the total ma
Alla [95]

Answer:

2.25 kg

Step-by-step explanation:

6 x 375 = 2250

1 kg = 1000 g

⇒ 2250 ÷ 1000 = 2.25 kg

5 0
2 years ago
Riley buys a swim pass for the pool in January. The first month costs $30. Each month after that, the cost is $20 per month.
Zanzabum

Answer:

you pay 240 dollars a year

Step-by-step explanation:

y=20x

x is 12

20*12=

240

6 0
3 years ago
Read 2 more answers
7 + 9y < -3 (y - 5) + 4
Anuta_ua [19.1K]

Answer:

y<1

Step-by-step explanation:

12y/12

12/12

5 0
3 years ago
Leah has three fewer than 4 times as many DVDs as Sonia has. Leah has 37 DVDs how many DVDs does sonia have
VashaNatasha [74]
X = sonias dvds

37 = 4x - 3
+3        +3

40 = 4x

10 = x

<span>sonia has 10 dvds</span>
4 0
3 years ago
Express this to single logarithm
zzz [600]

Answer:  \log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

  1. log(A) + log(B) = log(A*B)
  2. log(A) - log(B) = log(A/B)
  3. B*log(A) = log(A^B)

From there, we can then say the following:

\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}

8 0
2 years ago
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