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harkovskaia [24]
4 years ago
10

Which linear inequality is represented by the graph?

Mathematics
2 answers:
cricket20 [7]4 years ago
7 0

We will proceed to graph each case to determine the solution of the problem.

<u>case a)</u> y\leq x - 1.3

Using a graph tool

see the attached figure N 1

The solution is the shaded area

The inequality of the case a) is not  represented by the graph

<u>case b)</u> y\leq(x - 4)/3

Using a graph tool

see the attached figure N 2

The solution is the shaded area

The inequality of the case b) is represented by the graph

<u>case c) y \geq(x -4)/3</u>

Using a graph tool

see the attached figure N 3

The solution is the shaded area

The inequality of the case c) is not  represented by the graph

<u>case d) y \geq x -1.3</u>

Using a graph tool

see the attached figure N 4

The solution is the shaded area

The inequality of the case d) is not  represented by the graph

therefore

<u>the answer is</u>

The inequality y \leq (x - 4)/3 is represented by the graph

Olin [163]4 years ago
7 0

The line represents the inequality y \leqslant \frac{1}{3}x-1.3. Hence, \boxed{{\text{Option A}}} is correct.

Further explanation:

The linear equation with slope m and intercept c is given as follows.

\boxed{y=mx+c}

The formula for slope of line with points \left({{x_1},{y_1}}\right) and \left({{x_2},{y_2}}\right) can be expressed as,

\boxed{m=\frac{{{y_2}-{y_1}}}{{{x_2}-{x_1}}}}&#10;

Given:

The inequalities are as follows.

A. y \leqslant \frac{1}{3}x-1.3.

B. y \leqslant \frac{1}{3}x-\frac{4}{3}.

C. y \geqslant \frac{1}{3}x-\frac{4}{3}.

D. y \geqslant \frac{1}{3}x-1.3.

Explanation:

The line intersects y-axis at \left({0,-1.3}\right), therefore the y-intercept is -1.3.

The points are \left({0,-1.3}\right) and \left({3,-0.3}\right).

The slope of the line can be obtained as follows.

\begin{aligned}&#10;m&=\frac{{-0.3-\left({-1.3}\right)}}{{3-0}}\\&=\frac{{-0.3+1.3}}{3}\\&=\frac{1}{3}\\\end{aligned}&#10;

The slope of the line is m = \frac{1}{3}.

Now check whether the inequality included origin or not.

Substitute \left({0,0}\right) in the option A.

\begin{aligned}&#10;0\leqslant\frac{1}{3}\left(0\right)-1.3\hfill\\0\leqslant-1.3\hfill\\\end{aligned}&#10;

0 is not less than -1.3 which means that the inequality doesn’t includes origin.

The line represents the inequality y \leqslant \frac{1}{3}x-1.3. \boxed{{\text{Option A}}} is correct.

Option B is not correct as the y-intercept is not -1.3.

Option C is not correct as the y-intercept is not -1.3.

Option D is not correct as the inequality doesn’t include the origin.

Hence, \boxed{{\text{Option A}}} is correct.

Learn more:

1. Learn more about inverse of the function <u>brainly.com/question/1632445. </u>

2. Learn more about equation of circle <u>brainly.com/question/1506955. </u>

3. Learn more about range and domain of the function <u>brainly.com/question/3412497</u>

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Linear inequalities

Keywords: numbers, slope, slope intercept, inequality, equation, linear inequality, shaded region, y-intercept, graph, representation, origin.

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