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Anvisha [2.4K]
3 years ago
9

Exponents and Powers Question Need help, please answer with explanation.

Mathematics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

  a = -1

Step-by-step explanation:

The sign of a number raised to an even power is irrelevant. That means we can rewrite (-25)² as (-5)⁴. Doing so lets us combine the factors like so ...

  (-5)^{a+2}\times (-5)^4=(-5)^5\\\\(-5)^{a+2+4}=(-5)^5\\\\a+6=5 \qquad\text{equating exponents}\\\\a=-1 \qquad\text{subtract 6}

Here, we used the rule of exponents ...

  (a^b)(a^c) = a^(b+c)

_____

The business of "equating exponents" is equivalent to taking logarithms. In general, the logarithm of a number to a negative base is not defined. However, for the case of integer exponents we have here, there is no problem with doing what we did.

_____

<em>Check of the answer</em>

(-5)^1 × (-25)^2 = (-5)^5

-5 × 625 = -3125 . . . . true

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We need to simplify the given expression . The given expression is ,

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Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the <u>power is odd</u> .

Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,

\rm\implies\boxed{\quad \red{ -1 }\quad }

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>.</u>

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