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Klio2033 [76]
3 years ago
10

A man bought a bicycle for $400 and sold it at a loss of 35%. How much money did he lose?

Mathematics
1 answer:
DedPeter [7]3 years ago
8 0
If he bought the bike for $400 and lost 35% of his profit, you would divide 35 by 100. Next, you would multiply that number (0.35) by 400. When you do that, you get an answer of $140. In conclusion, if he bought the bike for $400 and sold it at a loss of 35%, he would lose $140 from that $400. 

Additionally, if you wanted to know what exactly he sold it for, you would simply subtract 140 from 400. Which would be $260.

So, he bought the bike for $400, but when he resold it, he lost $140 of that pay. Basically, he resold the bike for $260. 

I hope this helps! :) Let me know if you need help with anything else!
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The quotient of a number and 2 is the same as the difference of the number doubled and 3. What is the number?
blondinia [14]

Answer:

Step-by-step explanation:

x/2 = 2x-3

x = 4x-6

3x = 6

x = 2

7 0
2 years ago
A pair of basketball shoes was originally priced at 80. It was marked up by 37.5% what was the retail price of the shoes
OlgaM077 [116]

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67

Step-by-step explanation:

4 0
3 years ago
Please help its due in 1 hour it would be best if you show work
aleksley [76]

Answer:

1:quadrant 1

2:quadrant 1

3:quadrant 2

4:quadrant 3

5:quadrant 1

6:quadrant 4

7:Z and quadrant 2

8: F and quadrant 1

9:A and quadrant 4

10: R and quadrant 4

11: N and quadrant 2

12: Q and quadrant 3

13a:the clock

13b:wonder wheel

13c:big coaster

13d: -1,2

Good luck

6 0
2 years ago
Lori creates the following design for a T-shirt.
kakasveta [241]

<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7


Area of rectangle 1 = 8.68 sq.in

\Rightarrow FH \times HI=8.68

\Rightarrow EB \times HI=8.68  (∵ sides of the rectangle 2)

\Rightarrow 2.8 \times HI=8.68

\Rightarrow HI=3.1


Area of Triangle 1 = 6.48 sq.in

\Rightarrow \frac{1}{2}\times AE \times EG= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48  (∵ sides of the rectangle 1)

\Rightarrow EF+3.1= 5.4

\Rightarrow EF=2.3

\Rightarrow BH=2.3  (∵ sides of the rectangle 2)


BC = BH+HI+IC

\Rightarrow 11.7= 2.3+3.1+IC

\Rightarrow IC=6.3


The area of Rectangle 2,

=EB\times BH =2.8\times 2.3=6.44\ sq.in


The area of Triangle 2,

\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in


The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in


6 0
3 years ago
The measure of &lt;1 =<br><br> 040<br> 160<br> O
mafiozo [28]

Answer:

40

Step-by-step explanation:

As the total circumference of a circle is 360 degrees, the measure of the unknown arc is 360-150-130=80 degrees.

So, by the inscribed angle theorem, angle 1 measures 40 degrees.

8 0
1 year ago
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