Which of the following is not included in the appraisal report?

What is these in simplest form <br> a) 2a + 4 + 5a + 8 = <br> b) -2b – 7 + 3b – 8 =

iren [92.7K]

Answer:

a ) 7a + 12

b) b - 15

Step-by-step explanation:

a)2a+5a +8+8

= 7a + 12

b) b - 7 - 8

= b-15

6 0

3 years ago

A lab orders a shipment of 100 rats a week for experiments that the lab conducts. Prices for each weekly shipment of rats follow

Korolek [52]

Answer:

Therefore, the budget is 656.76$.

Step-by-step explanation:

We know that a lab orders a shipment of 100 rats a week for experiments that the lab conducts. Suppose the mean cost of the rats turned out to be $ 12.63 per week. We calculate budget of a lab for the next year's.

We know that 1 year have 52 weeks. We get

52 · 12.63 = 656.76

Therefore, the budget is 656.76$.

4 0

3 years ago

Read 2 more answers

Use the quadratic formula to findntge roots of the equation 2X2-28X+98=0

JulijaS [17]

The answer to that equation is {7,7}

3 0

3 years ago

Bryan bought 4 bags of peanuts from the grocery store. Each bag of has the

docker41 [41]

Answer:

141

Step-by-step explanation:

564 divided by 4 = 141

8 0

3 years ago

The personnel files of all eight employees at the Pawnee location of Acme Carpet Cleaners Inc. revealed that during the last six

irina [24]

Answer:

a) For Pawnee:

Range = 11, Mean = 3.13, Mean deviation = 2.44

For Chickpee:

Range = 7, Mean = 4.25, Mean deviation = 1.59

b) Pawnee Location has fewer lost days.

c) variation of the Chickpee is less than Pawnee location

Step-by-step explanation:

Data given:

For Pawnee:

3 1 0 0 2 11 5 3

Max = 11

Min = 0

Range = Max - Min

Range = 11-0 = 11

Range = 11

For Chickpee:

3 6 8 4 4 5 3 1

Max = 8

Min = 1

Range = Max - Min

Range = 8 - 1

Range = 7

For mean of Pawnee:

Mean = (3 + 1 + 0 + 0 + 2 + 11 + 5 + 3)/8

Mean = 25/8

Mean = 3.125

For mean deviation, we find the difference from the mean of each point.

Note: all the negative values will be taken as 0.

Differences from the mean of each point =

(3-3.13)=0.13, (1-3.31) = 2.13 ,

(0-3.13)=0, (0-3.13)=3.13,

(2-3.13)=1.13, (11-3.13)=7.87,

(5-3.13)=1.87, (3-3.13)=0.13

So, our differences are:

(0.13, 2.13, 0, 3.13, 1.13, 7.87, 1.87, 0.13 )

Mean deviation = Sum of all differences/8

Mean deviation = (0.13+2.13+3.13+3.13+ 1.13+ 7.87+ 1.87+ 0.13)/8

Mean deviation = 2.44

For mean of Chickpee:

Mean = (3+6+8+4+4+5+3+1)/8

Mean = 34/8

Mean = 4.25

Similarly, we need to find mean deviation for Chickpee, for that we need to find the differences first as done above for Pawnee.

Note: all the negative values will be taken as 0

Differences from the mean:

(3-4.25) = 1.25, (6-4.25) =1.75,

(8-4.25) = 3.75, (4-4.25)=0.25,

(4-4.25)=0.25, (5-4.25)= 0.75,

(3-4.25)=1.25, (1-4.25) =3.25

So, the differences are:

Differences = (1.25,1.75,3.75,0.25,0.25,0.75,1.25,3.25)

Mean deviation = (1.25+ 1.75+ 3.75+ 0.25+ 0.25+ 0.75+ 1.25+ 3.25)/8

Mean deviation = 1.59

b) which location has fewer lost days:

This can be found out by the total number of days of Pawnee and chickpee.

Pawnee = Sum of values = (3 + 1 + 0 + 0 + 2 + 11 + 5 + 3) = 25 days

Chickpee = Sum of values = (3+6+8+4+4+5+3+1) = 34 days

Hence, Pawnee Location has fewer lost days.

C) which location has less variation?

Formula for variation = ∑( $\frac{x^{2} }{8}$ ) - ( $mean^{2}$ )

where x = values of the set.

For Pawnee:

$mean^{2}$ = $3.13^{2}$ = 9.8

Sum of square of all the data points of Pawnee = 169

Variation = 169/8 - 98 = 11.325

Similarly,

For Chickpee:

$mean^{2}$ = $4.25^{2}$ = 18.06

Sum of square of all the data points of Chickpee = 176

Variation = 176/8 - 18.06

Variation = 22-18.06

Variation = 4

Hence, variation of the Chickpee is less than Pawnee location

8 0

3 years ago