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padilas [110]
3 years ago
11

If Ann correctly factors an expression that is the difference of two perfect squares, her factors could be

Mathematics
1 answer:
Sphinxa [80]3 years ago
3 0

Answer:

1.) ???

2.) (2x+3y)(2x-3y)=4x²-9y²

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Step-by-step explanation:

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4 years ago
Jacob transformed quadrilateral FGHJ to F'G'H'J'.
Rudik [331]

Answer:

A. Reflection across the line x = 1

Step-by-step explanation:  

Please find the attachment.

We have been given that Jacob transformed quadrilateral FGHJ to F'G'H'J'.  We are asked to find which transformation Jacob used to reflect FGHJ to F'G'H'J'.

Since we know that while reflecting a figure, the line of reflection will lie between the original figure and reflected figure. Each point of the reflected figure will have the same distance from the line of reflection as the corresponding point of the original figure.              

Now let us see our given choices one by one.

A. Reflection across the line x = 1.

Upon looking at point G and G' we can see that both points are equidistant (2 units) from the line x=1. Other corresponding points of both quadrilaterals are also equidistant from line x=1, therefore, Jacob used the reflection across the line x=1 to transform quadrilateral FGHJ to F'G'H'J'.

B. Reflection across the line y = 1 .      

If Jacob had reflected quadrilateral across line y=1, the points of quadrilateral F'G'H'J' will lie in second and third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option B is not a correct choice.

C. Reflection across the line y-axis.

If Jacob had reflected quadrilateral across y-axis, the coordinates of points of quadrilateral F'G'H'J' will be G'(1,4), H'(1,2), J'(4,0) and F'(2,5). Therefore, option B is not a correct choice.

D.  Reflection across the x -axis.

If Jacob had reflected quadrilateral across x-axis, the points of quadrilateral F'G'H'J' will lie in third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option D is not a correct choice.

3 0
3 years ago
An arrow is shot horizontally toward a target 20 m away. In traveling the first 5 m horizontally, the arrow falls 0.2 m. In trav
Elanso [62]

Answer:

The arrow will fall an additional 0.6 m.

Step-by-step explanation:

The height of the arrow can be calculated using the following kinematic equation of a falling object:

y = y0 + v0y · t + 1/2 · g · t²

Where:

y = height of the arrow at time "t"

y0 = initial height.

v0y = initial vertical velocity.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

t = time.

Since the arrow is shot horizontally, initially, it does not have a vertical velocity, so, v0y = 0.

If we place the origin of the frame of reference at the throwing point, y0 is also 0. Then:

y = 1/2 · g · t²

First, let´s calculate how much time it takes for the arrow to travel 5 m. It will be the time it takes the arrow to fall 0.2 m. Then, using the equation of height:

y = 1/2 · g · t²

-0.2 m = 1/2 · (-9.8 m/s²) · t²     (notice that we consider the upward direction as positive and the origin of the frame of reference is at the throwing point).

-0.2 m / -(1/2 · 9.8 m/s²) = t²

t = 0.2 s

If we neglect air resistance, the horizontal velocity of the arrow will be constant because there is no force acting in the horizontal direction on the arrow. Then, the arrow will travel the next 5 m in another 0.2 s. Then, let´s find the height of the arrow at t = 0.4 s.

y = 1/2 · g · t²

Instead of t = 0.4 s I will use t = 2 · √(-0.2 m / -(1/2 · 9.8 m/s²))  (this expression was obtained above) to avoid error because of rounding:

y = 1/2 · (-9.8² m/s) · (2 · √(-0.2 m / -(1/2 · 9.8 m/s²)))²

y = -0.8 m

The height of the arrow when it travels another 5 m will be -0.8 m (0.8 m below the throwing point). It means that the arrow will fall an additional 0.6 m.

6 0
4 years ago
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