Hi there
1/8 * 3/4
Remember: When you are multiply two fractions together all you have to do is multiply the numerator by the denominator.
Answer : 3/32
I hope that's help !
Answer:
c
Step-by-step explanation:
the normal equation is 120 and c is 120
Answer:
Test statistic, 
(to 3 dp)
Step-by-step explanation:
Deviation, d = x -y
Sample mean for the deviation
Standard deviation: 
SD =2.93
Under the null hypothesis, the formula for the test statistics will be given by:
Lateral faces are all the sides of the prisms EXCEPT the bases, which are the sides on the top and bottom. To find the area of the lateral faces we can use the formula: perimeter x height.
perimeter = 2 (6 + 8) = 2 x 14 = 28
height = 14
area of the lateral faces = perimeter x height = 28 x 14 = 392
Hope this helps!
Answer:
a. 25.98i - 15j mi/h
b. 1.71i + 4.7j mi/h
c. 27.69i -10.3j mi/h
Step-by-step explanation:
a. Identify the ship's vector
Since the ship moves through water at 30 miles per hour at an angle of 30° south of east, which is in the fourth quadrant. So, the x-component of the ship's velocity is v₁ = 30cos30° = 25.98 mi/h and the y-component of the ship's velocity is v₂ = -30sin30° = -15 mi/h
Thus the ship's velocity vector as ship moves through the water v = v₁i + v₂j = 25.98i + (-15)j = 25.98i - 15j mi/h
b. Identify the water current's vector
Also, since the water is moving at 5 miles per hour at an angle of 20° south of east, this implies that it is moving at an angle 90° - 20° = 70° east of north, which is in the first quadrant. So, the x-component of the water's velocity is v₃ = 5cos70° = 1.71 mi/h and the y-component of the water's velocity is v₄ = 5sin70° = 4.7 mi/h
Thus the ship's velocity vector v' = v₃i + v₄j = 1.71i + 4.7j mi/h
c. Identify the vector representing the ship's actual motion.
The velocity vector representing the ship's actual motion is V = velocity vector of ship as ship moves through water + velocity vector of water current.
V = v + v'
= 25.98i - 15j mi/h + 1.71i + 4.7j mi/h
= (25.98i + 1.71i + 4.7j - 15j )mi/h
= 27.68i -10.3j mi/h
