1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zarrin [17]
3 years ago
10

Ujalakhan01! Please help me! ASAP ONLY UJALAKHAN01. What's (x-1)(x-1)?

Mathematics
2 answers:
bogdanovich [222]3 years ago
5 0

Answer:

Step-by-step explanation:

simply :

  • (x-1)(x-1)= (x-1)²

                     = x²-2x=1

                     

patriot [66]3 years ago
4 0

Answer:

x^2-2x+1

Step-by-step explanation:

=> (x-1)(x-1)

Using FOIL

=> x^2-x-x+1

=> x^2-2x+1

You might be interested in
8 1/2 minus 7 1/4 in fraction form?
barxatty [35]

Answer:

1  1/4

1.25

Step-by-step explanation:

8 0
3 years ago
Decide if the following statement is valid or invalid. If two sides of a triangle are congruent then the triangle is isosceles.
Naya [18.7K]

Answer:

Step-by-step explanation:

Properties of an Isosceles Triangle

(Most of this can be found in Chapter 1 of B&B.)

Definition: A triangle is isosceles if two if its sides are equal.

We want to prove the following properties of isosceles triangles.

Theorem: Let ABC be an isosceles triangle with AB = AC.  Let M denote the midpoint of BC (i.e., M is the point on BC for which MB = MC).  Then

a)      Triangle ABM is congruent to triangle ACM.

b)      Angle ABC = Angle ACB (base angles are equal)

c)      Angle AMB = Angle AMC = right angle.

d)      Angle BAM = angle CAM

Corollary: Consequently, from these facts and the definitions:

Ray AM is the angle bisector of angle BAC.

Line AM is the altitude of triangle ABC through A.

Line AM is the perpendicular bisector of B

Segment AM is the median of triangle ABC through A.

Proof #1 of Theorem (after B&B)

Let the angle bisector of BAC intersect segment BC at point D.  

Since ray AD is the angle bisector, angle BAD = angle CAD.  

The segment AD = AD = itself.

Also, AB = AC since the triangle is isosceles.

Thus, triangle BAD is congruent to CAD by SAS (side-angle-side).

This means that triangle BAD = triangle CAD, and corresponding sides and angles are equal, namely:

DB = DC,

angle ABD = angle ACD,

angle ADB = angle ADC.

(Proof of a).  Since DB = DC, this means D = M by definition of the midpoint.  Thus triangle ABM = triangle ACM.

(Proof of b) Since angle ABD = angle ABC (same angle) and also angle ACD = angle ACB, this implies angle ABC = angle ACB.

(Proof of c) From congruence of triangles, angle AMB = angle AMC.  But by addition of angles, angle AMB + angle AMC = straight angle = 180 degrees.  Thus 2 angle AMB = straight angle and angle AMB = right angle.

(Proof of d) Since D = M, the congruence angle BAM = angle CAM follows from the definition of D.  (These are also corresponding angles in congruent triangles ABM and ACM.)

QED*

*Note:  There is one point of this proof that needs a more careful “protractor axiom”.  When we constructed the angle bisector of BAC, we assumed that this ray intersects segment BC.  This can’t be quite deduced from the B&B form of the axioms.  One of the axioms needs a little strengthening.

The other statements are immediate consequence of these relations and the definitions of angle bisector, altitude, perpendicular bisector, and median.  (Look them up!)

Definition:  We will call the special line AM the line of symmetry of the isosceles triangle.  Thus we can construct AM as the line through A and the midpoint, or the angle bisector, or altitude or perpendicular bisector of BC. Shortly we will give a general definition of line of symmetry that applies to many kinds of figure.

Proof #2 (This is a slick use of SAS, not presented Monday.  We may discuss in class Wednesday.)

The hypothesis of the theorem is that AB = AC.  Also, AC = AB (!) and angle BAC = angle CAB (same angle).  Thus triangle BAC is congruent to triangle BAC by SAS.

The corresponding angles and sides are equal, so the base angle ABC = angle ACB.

Let M be the midpoint of BC.  By definition of midpoint, MB = MC. Also the equality of base angles gives angle ABM = angle ABC = angle ACB = angle ACM.  Since we already are given BA = CA, this means that triangle ABM = triangle ACM by SAS.

From these congruent triangles then we conclude as before:

Angle BAM = angle CAM (so ray AM is the bisector of angle BAC)

Angle AMB = angle AMC = right angle (so line MA is the perpendicular bisector of  BC and also the altitude of ABC through A)

QED

Faulty Proof #3.  Can you find the hole in this proof?)

In triangle ABC, AB = AC.  Let M be the midpoint and MA be the perpendicular bisector of BC.

Then angle BMA = angle CMA = right angle, since MA is perpendicular bisector.  

MB = MC by definition of midpoint. (M is midpoint since MA is perpendicular bisector.)

AM = AM (self).

So triangle AMB = triangle AMC by SAS.

Then the other equal angles ABC = ACB and angle BAM = angle CAM follow from corresponding parts of congruent triangles.  And the rest is as before.

QED??

8 0
2 years ago
What is the Median for the following set of numbers? ​21 23 76 47 55 135 45 30 17
Leno4ka [110]

Answer:

Median = 45

Step-by-step explanation:

We are given the following data set:

21, 23, 76, 47, 55, 135, 45, 30, 17

Median is the number that divides the data into two equal parts.

Formula:

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data:

17, 21, 23, 30, 45, 47, 55, 76, 135

Sample size = 9, which is odd

Median =

\dfrac{9+1}{2}^{th}\text{ term} = \dfrac{10}{2}^{th}\text{ term} = 5^{th}\text{ term}\\\\= 45

The median of given set of numbers is 45.

7 0
3 years ago
Suppose that the perimeter a rectangle is 54 feet, and the length is 13 feet more than the width. Find the width ractangle, in f
Vesnalui [34]

Answer:7feet

Step-by-step explanation:

perimeter(p)=54ft

Width(w) +13=Length(L)

Perimeter=2xLength+2xwidth

P=2xL+2xw

L=w+13

54=2(w+13)+2w

54=2w+26+2w

Collect like terms

54-26=2w+2w

28=4w

Divide both sides by 4

28/4=4w/4

7=w

Width =7feet

8 0
3 years ago
What percentage of 5/2 hours is 15 minutes?​
elena-14-01-66 [18.8K]

Answer:

10 %

Step-by-step explanation:

15 mn = 1/4 h

We have :

\frac{\frac{1}{4} }{\frac{5}{2} } =\frac{1}{4} \times \frac{2}{5} =\frac{2}{20} =\frac{1}{10}=0.1

Then the percentage that 15 mn represents of 5/2 h is :

0.1 × 100 = 10 %

5 0
2 years ago
Other questions:
  • What type of fractions are the following ​
    5·1 answer
  • Can someone check my work?
    6·1 answer
  • What is the value of 2 in 5,670,249,114? And describe 2 ways to find value?
    6·1 answer
  • New York City is the most expensive city in the United States for lodging. The mean hotel room rate is $204 per night (USA Today
    15·1 answer
  • Please help 100 points if correct answer!
    6·1 answer
  • Baldwin paid $48 for 4 movie tickets. Each ticket costs the same amount. What was the cost of each movie ticket?
    5·2 answers
  • Josue needs 2 1/4 cups of flour to make a batch of chocolate chip cookies. He needs to make 5 batches for the bake sale. How man
    13·2 answers
  • A circular tablecloth covers a table with a diameter of 5 feet. How much trim is needed to put around the edges of the tableclot
    9·1 answer
  • HELPPPPPPPPPP!!! pls show work
    10·1 answer
  • Mark spent 1 hour 17 minutes less than Sheila reading last week. Sheila spent 55 minutes less than Pete. Pete spent 3 hours read
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!