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3 years ago

Determine the value of f(2) that will lead to an average rate of change of 15 over the interval [2,6]. (HELP PLEASE)

Mathematics

1 answer:

Fofino [41]3 years ago

6 0

Average Rate of Change/Slope Formula: $\frac{y_2-y_1}{x_2-x_1}$

So using points (6,71) and (2,y), and the slope of 15, plug them into the slope formula as such:

$\frac{71-y}{6-2}=15$

From here we can solve for y. Firstly, solve the subtraction:

$\frac{71-y}{4}=15$

Next, multiply both sides by 4:

$71-y=60$

Next, subtact both sides by 71:

$-y=-11$

Lastly, multiply both sides by -1, and <u>your final answer will be $y=11$ , or A.</u>

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Answer:

2 & +2i

Step-by-step explanation:

The two additional roots of the polynomial functions are:

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3 years ago

What's the solution for y+1/2=3/4

creativ13 [48]

$\frac{y+1}{2} = \frac{3}{4}$

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3 years ago

Jason is pulling a box across the room. He is pulling with a force of 11 newtons and his arm is making a 37 angle with the horiz

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Force=10N

Angle=37

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2 years ago

During the first decade of the century, the population of a certain city was 145,380 in 2000 and 219,135 in 2010. Find the expon

Likurg_2 [28]

Answer:

The exponential growth function is $P=145380e^{0.04103t}$

Step-by-step explanation:

Given: The population of a certain city was 145,380 in 2000 and 219,135 in 2010.

To find: exponential growth function that models the growth of the city

Solution:

The exponential growth function is given by $P=P_0 e^{kt}$

Here, P denotes total population after time t

$P_0$ denotes initial population

k denotes rate of growth

t denotes time

As $P(0)=145,380$ ,

$145380=P_0e^{0}\\145380=P_0\\P=145380e^{kt}$

As $P(10)=219135$

$219135=145380e^{10k}\\e^{10k}=\frac{219135}{145380}\\=1.507326\\k=\frac{1}{10}\ln (1.507326)\\=0.04103\\\Rightarrow P=145380e^{0.04103t}$

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3 years ago

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NeX [460]

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Here are the answers for the first three:

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2) $4w^2 + 14w + 17$

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3 years ago

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