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mihalych1998 [28]
3 years ago
12

Dvide if the polynomial does not divide evenly. Include the remainder as a fraction (18u^2 - 142u - 11) ÷ (u - 8)​

Mathematics
2 answers:
Mashutka [201]3 years ago
6 0

Answer:

  • 18u + 2 + 5/(u - 8)

Step-by-step explanation:

  • (18u^2 - 142u - 11) ÷ (u - 8)​

  • 18u^2 - 142u - 11 =
  • 18u^2 - 8*18u + 2u - 11 =
  • 18u(u - 8) + 2u - 16 + 5 =
  • 18u(u - 8) + 2(u - 8) + 5 =
  • (18u + 2)(u - 8) + 5

  • (18u^2 - 142u - 11) ÷ (u - 8)​  = 18u + 2 + 5/(u - 8)
stich3 [128]3 years ago
5 0

Answer:

18u + 2 + 5/u - 8.

Step-by-step explanation:

(18u^2 - 142u - 11) ÷ (u - 8)

= 18u + 2 + 5/u - 8.

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At the banquet 450 people had chicken and 150 had pasta. What percent of people has pasta?
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25 percent of people had pasta.

First add 450 and 150 (which equals 600)

Next divide 600 by 150 (which equals 4)

Which means 150 is a fourth of six hundred, and a fourth is 25 percent.

Which leads to my answer of 25 percent

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3 years ago
A science class has 5 girls and 5 boys in the seventh grade and 3 girls and 5 boys in the eighth grade. The teacher randomly sel
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So the ratios are 5:5 and 3:5 so the fractions are 5/10 (1/2) for 7th grade and 5/8 for 8th grade
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Read 2 more answers
Choose ALL possible answers
muminat
Select all the correct answers:
1) Yes

2) No
x=8→h(8)=2(8)^2+5(8)+2=2(64)+40+2=128+40+2→h(8)=170
x=8→f(8)=3^8+2=6,561+2→f(8)=5,563>170=h(8)

3) Yes

4) No

5) Yes
rg=[g(3)-g(2)]/(3-2)=[g(3)-g(2)]/1→rg=g(3)-g(2)
g(3)=20(3)+4=60+4→g(3)=64
g(2)=20(2)+4=40+4→g(2)=44
rg=64-44→rg=20

rf=f(3)-f(2)
f(3)=3^3+2=27+2→f(3)=29
f(2)=3^2+2=9+2→f(2)=11
rf=29-11→rf=18

rh=h(3)-h(2)
h(3)=2(3)^2+5(3)+2=2(9)+15+2=18+15+2→h(3)=35
h(2)=2(2)^2+5(2)+2=2(4)+10+2=8+10+2→h(2)=20
rh=35-20→rh=15

rg=20>18=rf
rg=20>15=rh

6)  No
x=4→g(4)=20(4)+4=80+4→g(4)=84
x=4→h(4)=2(4)^2+5(4)+2=2(16)+20+2=32+20+2→h(4)=54
x=4→f(4)=3^4+2=81+2→f(4)=83>54=h(4)
f(4)=83<84=g(4)
7 0
3 years ago
A researcher determines that students are active about 60 + 12 (M + SD) minutes per day. Assuming these data are normally distri
rjkz [21]

Answer:

The correct option is (b).

Step-by-step explanation:

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variate is known as the standard normal distribution.

The mean and standard deviation of the active minutes of students is:

<em>μ</em> = 60 minutes

<em>σ </em> = 12 minutes

Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Z=\frac{X-\mu}{\sigma}=\frac{48-60}{12}=\frac{-12}{12}=-1.0

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.

The correct option is (b).

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Match each sentence with the inequality that could represent the situation
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Woahhhh whattt I don’t even know bro
3 0
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