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3 years ago

SDAY: ve the equation: 5x – 2(x + 7) = -5

Mathematics

1 answer:

pogonyaev3 years ago

5 0

5x – 2(x + 7) = -5

mutiply the bracket by -2

(-2)(x)= -2x

(-2)(7)= -14

5x-2x-14=-5

3x-14= -5

move -14 to the other side, sign changes from -14 to +14

3x-14+14= -5+14

3x= 9

divide by 3 for both sides

3x/3= 9/3

x= 3

Answer: x= 3

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0.3(4-x)=x-1.4 how do you solve this problem?

tresset_1 [31]

Answer:

x = 2.

Step-by-step explanation:

Solve for x:

0.3 (4 - x) = x - 1.4

Expand out terms of the left hand side:

1.2 - 0.3 x = x - 1.4

Subtract x from both sides:

1.2 + (-0.3 x - x) = (x - x) - 1.4

-0.3 x - x = -1.3 x:

-1.3 x + 1.2 = (x - x) - 1.4

x - x = 0:

1.2 - 1.3 x = -1.4

Subtract 1.2` from both sides:

(1.2 - 1.2) - 1.3 x = -1.2 - 1.4

1.2 - 1.2 = 0:

-1.3 x = -1.2 - 1.4

-1.2 - 1.4 = -2.6:

-1.3 x = -2.6

Divide both sides of -1.3 x = -2.6 by -1.3:

(-1.3 x)/(-1.3) = (-2.6)/(-1.3)

(-1.3)/(-1.3) = 1:

x = (-2.6)/(-1.3)

(-2.6)/(-1.3) = 2.:

Answer: x = 2.

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3 years ago

Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how

astra-53 [7]

Answer:

When Aria sold her house after eleven years it worth was $95,300.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be $x.$

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

$x=A\times (1+\frac{r}{100})^{11}$

$x=75000\times (1+\frac{2.2}{100})^{11}$

$x=75000\times (1+0.022)^{11}$

$x=75000\times (1.022)^{11}$

$x=75000\times 1.2704$

$x=95280.$

The amount of house after eleven years to the nearest hundred dollars is $95,300.

Therefore, when Aria sold her house after eleven years it worth was $95,300.

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Harlamova29_29 [7]

Answer:4x+30

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