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Ratling [72]
4 years ago
14

Find the coordinates of P(a,b) whose ordinate is twice as much as abscissa and sum of coordinates is -12.

Mathematics
1 answer:
ser-zykov [4K]4 years ago
8 0

Answer:

P(- 4, - 8 )

Step-by-step explanation:

The abscissa is the x- coordinate and the ordinate is the y- coordinate.

Here b = 2a , thus

a + 2a = - 12

3a = - 12 ( divide both sides by 3 )

a = - 4

and b = 2a = 2 × - 4 = - 8

P(- 4, - 8 )

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