The point which would lie on the graph of f(x) = log2x is; (1, 0.301).
<h3>Which point would lie on the graph of f(x) = log2x?</h3>
Since it follows from the task content that the given point (–1, 0.5) lies on the graph of f –1(x) = 2x.
The subsequent graph of f(x) = log2x would result from taking logarithms in which case, we have the graph passing through points determined as follows;
f(x) = log2^x
f(x) = x log2
Hence, when x = 1;
f(1) = 1log 2
Hence, we have point; (1, 0.301).
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The answer would be 23 on the third term
Solve for x first
-6x - 42 = -4x -2
-6x = -4x + 40
- 2x = 40
X = -20
The equation has one solution
Answer:
5x and -4x
Step-by-step explanation:
Paul wants M₁ and M₂ to have a total that is +x, and a product that is -20x². The values of M₁ and M₂ that will do that are ...
5x and -4x
