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Rzqust [24]
3 years ago
11

What value of n makes the equation true?

Mathematics
2 answers:
dsp733 years ago
7 0
SE NÃO ME ENGANO A RESPOSTA É A 10
marishachu [46]3 years ago
7 0

Answer: <u>(Brainlesssss plsssssss)</u>

10

explaniion:

given that:

(2x^9y^n)(4x^2y^10)=8x^11y^20

the value of n that will make the inequality true will be found as follows;

(2x^9y^n)(4x^2y^10)=8x^11y^(n+10)

thus;

8x^11y^(n+10)=8x^11y^20

dividing through by 8x^11 we get;

y^(n+10)=y^20

introducing the natural logs we get;

(n+10)lny=20lny

lny will cancel out and we shall remain with;

n+10=20

thus

n=20-10

n=10

the answer is n=10

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\frac{ {w}^{2}  - 7w + 12}{ {w}^{2}  + w - 20 }

EXPLANATION


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