Answer:
An interpreter is quite different from a complier due to the following statement below:
O. An interpreter translates and executes code line by line, while a compiler translates all code at once so that it is ready to be executed at any time.
Explanation:
For an interpreter, it works in translating and execution of the codes line after another line. In a situation where there is a mistake in the code, the next line would not be able to be executed, but rather display error message. On the other hand, compiler translate all codes at once and execute them as a single work.
<em>During its translation of the codes in compiler, should there be any error, it would not be able to execute despite the fact that, the error might be in the last line of the code.</em>
There are three tunneling protocols. They are ISATAP, <span>teredo and 6TO4</span><span />
Answer:
The answer to this question is given below in the explanation section. the correct option is C.
Explanation:
This is Java code statement:
System.out.print("Computing\nisInfun");
The output of this code statement is
Computing
isInfun
However, it is noted that the C option is not written correctly, but it is guessed that it will match to option C.
This Java code statement first prints "Computing" and then on the next line it will print "isInfun" because after the word "Computing" there is a line terminator i.e. \n. when \n will appear, the compiler prints the remaining text in the statement on the next line.
Answer:
The sum of all positive even values in arr
Explanation:
We have an array named arr holding int values
Inside the method mystery:
Two variables s1 and s2 are initialized as 0
A for loop is created iterating through the arr array. Inside the loop:
num is set to the ith position of the arr (num will hold the each value in arr)
Then, we have an if statement that checks if num is greater than 0 (if it is positive number) and if num mod 2 is equal to 0 (if it is an even number). If these conditions are satisfied, num will be added to the s1 (cumulative sum). If num is less than 0 (if it is a negative number), num will be added to the s2 (cumulative sum).
When the loop is done, the value of s1 and s2 is printed.
As you can see, s1 holds the sum of positive even values in the arr
