Answer:
Check the explanation
Explanation:
Yes, going by the question above, the protocol validates Bob to Alice for the reason that the key is only shared between Bob and Alice as well as the number which is being sent randomly. Therefore the invader won’t be able to predict and response to that number. Because of the authentication protocol, that makes use of a classical cryptosystem thereby resulting into the possibility of an argument such that key finding is attainable via invader.
Answer:
import java.util.Scanner;
public class num8 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter month's budget");
double monthBudget = in.nextDouble();
double totalExpenses = 0.0;
double n;
do{
System.out.println("Enter expenses Enter zero to stop");
n = in.nextDouble();
totalExpenses += n;
}while(n>0);
System.out.println("Total expenses is "+totalExpenses);
System.out.println("The amount over your budget is "+ Math.abs(monthBudget-totalExpenses));
}
}
Explanation:
- Using Java programming language
- Prompt user for month's budget
- Use Scanner class to receive and store the amount entered in a variable
- Use a do while loop to continuously request user to enter amount of expenses
- Use a variable totalExpenses to add up all the expenses inside the do while loop
- Terminate the loop when user enters 0 as amount.
- Subtract totalExpenses from monthBudget and display the difference as the amount over the budget
Lexeme is a category or partitioned group of the small units of a programming language include its numeric literals, operators, and special words.
<h3>What is a lexeme in programming?</h3>
Lexemes are known to be those character strings that are put together from the character group of a program, and the token stands for what aspect of the program's grammar they are made of.
Hence, Lexeme is a category or partitioned group of the small units of a programming language include its numeric literals, operators, and special words.
Learn more about Lexeme from
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Answer:
0
Explanation:
In the problem above, the relationship that exists between M and N is discovered to be on each side of the system. Furthermore, it was stated that the outcome of the relationship also has approximately 3 records. This shows that there is no record for the bridge that is formed as a result of the relationship.
