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3 years ago

What is the solution to 0= -6n

Mathematics

1 answer:

HACTEHA [7]3 years ago

7 0

The solution is 6=n

6+0=6+(-6)n

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Solve: y= -5<br> x= y + 3<br>what is the pair (_,_)

olga nikolaevna [1]

We are given $y=-5$ . Substituting, $x=y+3=-5+3=-2$ .

Thus, our ordered pair $(x, y)$ is $(-2, -5)$ .

8 0

3 years ago

Read 2 more answers

Which experession is equivalent to

Readme [11.4K]

Hey there!

8x + 4y - 2x + 6y - 3
COMBINE the LIKE TERMS

= (8x - 2x) + (4y + 6y) - (3)

= 8x - 2x + 4y + 6y - 3

= 6x + 10y - 3

Therefore, your answer is:

6x + 10y - 3 (Optipn A.)

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

7 0

2 years ago

Read 2 more answers

Pls help if u can 6thgrade math

motikmotik

Answer:

Greatest number: 9

Least number: 2

Range: 7

Step-by-step explanation:

From smallest to largest, the numbers are: 2, 3, 6, 8, 9. The largest (greatest) is 9 and the least (smallest) is 2. The range is 9-2=7.

7 0

3 years ago

Inverse laplace of L^-1 {5s/s^2 + 3s - 4}

Salsk061 [2.6K]

Answer:

$e^t+e^{-4t}$

Step-by-step explanation:

We have to simplify the original function using partial fraction, hence:

$\frac{5s}{s^2+3s-4} =\frac{5s}{(s-1)(s+4)}\\\\=\frac{A}{s-1}+\frac{B}{s+4}\\\\Therefore:\\\\\frac{A(s+4)+B(s-1)}{(s-1)(s+4)}=\frac{5s}{(s-1)(s+4)}\\\\Eliminating\ the \ denominator:\\\\A(s+4)+B(s-1)=5s\\\\substitute\ s=1:\\\\A(1+4)+B(1-1)=5(1)\\\\5A=5\\\\A=1\\\\tsubstitute\ s=-4:\\\\A(-4+4)+B(-4-1)=5(-4)\\\\-5B=-20\\\\B=4\\\\Therefore\ substituting\ A\ and\ B\ gives:\\\\\frac{5s}{s^2+3s-4}=\frac{1}{s-1}+ \frac{4}{s+4}\\\\$

$From\ Laplace\ inverse:\\\\But\ L^{-1}[\frac{1}{s-a} ]=e^{at}\\\\Hence:\\\\L^{-1} [\frac{5s}{s^2+3s-4}]=L^{-1}[\frac{1}{s-1} ]+L^{-1}[\frac{4}{s+4} ]=e^{t}+4e^{-4t}\\\\L^{-1} [\frac{5s}{s^2+3s-4}]=e^{t}+4e^{-4t}$

5 0

3 years ago

For the function f(x)=3xsquared- 2x+5 find f(1) f(-2) and f(a)

Oksanka [162]

$f(x)=3x^2-2x+5\\\\
f(1):\ \ Substitude\ 1 \ as\ x\ into\ function:\\
f(1)=3*1^2-2*1+5=3-2+5=\textbf{6}\\\\
f(-2)\ \ Substitude\ x=-2\\
f(-2)=3*(-2)^2-2*(-2)+5=3*4+4+5=12+4+5=\textbf{21}\\\\
f(a)\ \ substitude\ x=a\\
f(a)=\underline{3a^2-2a+5}$

4 0

4 years ago