What is the sum of the interior angles of the following convex polygon?
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Angle a is directly opposite from a 40 degree angle, so a=40. Then we can find b since the sum of the angles of all triangles is 180 and there is a right angle in there along with angle a:
Last, to find c we just notice that it is supplementary with an angle of measure 65, so:
So our angles are a=40, b=50, c=115.
Last, to find c we just notice that it is supplementary with an angle of measure 65, so:
So our angles are a=40, b=50, c=115.