Step-by-step explanation:
The Chord Intersection Theorem:
If 2 chords of a circle are AB and CD and they intersect at E, then
AE * EB = CE * ED.
Problem.
Two Chords AB and CD intersect at E. If AE = 2cm , EB = 4 and CE = 2.5 cm, find the length of ED.
By the above theorem : 2 * 4 = 2.5 * ED
ED = (2 * 4) / 2.5
= 3.2 cm.
is this what u wanted??????????
Answer:
b. x = -3
Step-by-step explanation:
0 = x^2 + 6x + 9
Factor
0 = (x+3) (x+3)
Using the zero product property
x+3 = 0 x+3 =0
x = -3
Let
x------> the <span>height of a cylinder
y------> the radius </span>of a cylinder
we know that
x=5y
[t<span>he lateral area of the cylinder]=[perimeter of the base]*height
</span>[perimeter of the base]=2*pi*r-------> 2*pi*y
[the lateral area of the cylinder]=[2*pi*y]*(5y)-----> 10*pi*y²
10*pi*y²=360*pi-----> y²=36--------> y=6 units
<span>
the answer is
</span><span>the length of the radius of the cylinder is 6 units</span><span>
</span>
C I'm using the calculator and the other ones don't make sense
Answer:
2/3 = 8/12
Step-by-step explanation:
2/3 vs 8/12
Multiply the left by 4/4 to get common denominators
2/3 *4/4 = 8/12
They are equal