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3 years ago

8

Solve the inequality. Graph the solution set on a number line. P+5>-3 and p+1<4

2 answers:

juin [17]3 years ago

4 0

for the first inequality subtract 5 from both sides and then you would get p>-8 now the second inequality subtract one from both sides and you get p<3 to graph you put them both on a number line at their spots with a open circle surrounding the point for both inequalitys.

hope this helps

fomenos3 years ago

3 0

Answer: -8< P <3

Step-by-step explanation:

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C is the correct answer

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Elementary and secondary schools were classified by the number of computers they had.

Keith_Richards [23]

Answer:

$Probability = 0.7259$

$Probability = 0.2741$

$Probability = 0.4414$

Step-by-step explanation:

Given

The table

First, we calculate the amount of schools

$Total = 752 + 3352 + 18865 + 14016 + 46805$

$Total = 83790$

Solving (a): Probability of 75+ computers.

From the given table, schools with 75 or more computers have the population of:

$75\ or\ more = 14016 + 46805$

$75\ or\ more = 60821$

The probability is calculated as:

$Probability = \frac{75\ or\ more}{Total}$

$Probability = \frac{60821}{83790}$

$Probability = 0.7259$

Solving (b): Probability of less than 75 computers.

From the given table, schools with less than 75 computers have the population of:

$Less\ than\ 75 = 752 + 3352 +18865$

$Less\ than\ 75 = 22969$

The probability is calculated as:

$Probability = \frac{Less\ than\ 75}{Total}$

$Probability = \frac{22969}{83790}$

$Probability = 0.2741$

Solving (c): Probability of less than 10 computers.

From the given table, schools with less than 100 computers have the population of:

$Less\ than\ 100 = 752 + 3352 +18865+14016$

$Less\ than\ 100 = 36985$

The probability is calculated as:

$Probability = \frac{Less\ than\ 100}{Total}$

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Step-by-step explanation:

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Answer:

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yuradex [85]

Answer:

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Step-by-step explanation:

⇒ $p(x)=x^{3} -x^{2} -4x-6$

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now, for zeros of $(x^{2} +2x+2)$ ,

⇒ x = $\frac{-b}{2a}$ ± $\frac{\sqrt{b^{2}-4ac } }{2a}$

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