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lord [1]
3 years ago
14

How do i create a predictable sequence of at least 4 numbers that is NOT arithmetic or geometric?

Mathematics
1 answer:
g100num [7]3 years ago
3 0
Numbers that are already in order are predictable.
Example:1,2,3,4
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What is the lateral surface area of the solid? Assume the top and bottom of
timama [110]

Check the picture below.

so the lateral area will be just the area of the sides, namely excluding the bases at top and bottom, thus

\stackrel{\textit{\LARGE Lateral Area}}{\stackrel{\textit{front and back}}{2(4)(5)}~~ + ~~\stackrel{\textit{left and right}}{2(4)(7)}}\implies 40~~ + ~~56\implies 96~cm^2

4 0
2 years ago
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You are studying for your final exam on the semester. Up to this point, you received 3 exam scores of 99%, 80%, And 70%. To rece
Alchen [17]
80*4=320
89*4=356
This is the range of the addition of all 4 scores.

99+80+70=249

320-249= 71
356-249= 107

[71, 100] would be the answer, unless you can get extra credit on the final.
5 0
3 years ago
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find the mean, range ,and median of these values 12,4,-2,0,9.-2,1,7,8,2 recall the range is calculated by finding the difference
Lubov Fominskaja [6]
Put numbers in order
-2,-2,0,1,2,4,7,8,9,12
Mean add all the numbers = 39 divide 39 by the number of of numbers on the list which is 10. 39/10 = 3.9
Mean = 3.9
Range is the number of spots between -2 and 12 = 14
Range =14
Median is the middle number in the list there are two middle numbers 2 and 4. Add these together to get 6. Divide 6 by the number 2 because that is how many numbers you had to add. 6/2=3. The is not on the list but it is the average of the two terms.
Median =3
8 0
3 years ago
Classify the triangle with side lengths 4,4, and 4. right equilateral scalene isosceles
balu736 [363]

It is a equilateral

Equilateral triangles are triangles that have measurements of the same lengths on all sides

5 0
3 years ago
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Given the volume of Figure A is 512cm ^3and Figure B is 343cm^3, find the ratio of the perimeter from Figure A to Figure B.
sp2606 [1]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\[2em] \begin{array}{ccccllll} &\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\ \cline{2-4}&\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}\\\\[-0.35em] ~\dotfill

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{\textit{figure A}}{\textit{figure B}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{512}}{\sqrt[3]{343}}\qquad \begin{cases} 512=&2^9\\ &2^{3\cdot 3}\\ &(2^3)^3\\ 343=&7^3 \end{cases}\implies \cfrac{s}{s}=\cfrac{\sqrt[3]{(2^3)^3}}{\sqrt[3]{7^3}} \\\\\\ \cfrac{s}{s}=\cfrac{2^3}{7}\implies \cfrac{s}{s}=\cfrac{8}{7}\implies s:s = 8:7\impliedby \textit{ratio of the }\stackrel{sides~and}{perimeters}

5 0
3 years ago
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