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2 years ago

HeLp wilL GiVe BraNIliEsT

Mathematics

1 answer:

sammy [17]2 years ago

3 0

Answer:

Question A is satistical

Step-by-step explanation:

a satistical question is a question that you can answer by collecting data

sence you will need the temperatures for December for each 10 years that would be data unlike question B.

Question B: you will need to collect the warmest temperature in December from the past 10 years.

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Which number is irrational...please help!!

yKpoI14uk [10]

Answer:

D I think

Step-by-step explanation:

7 0

3 years ago

22. A rectangular container, whose base is a square

Pie

Answer:

the will be volume is 6cm

7 0

3 years ago

Use substitution to solve the sy 2x+3y = 19 x = 2y-1 Solve for x and y

svp [43]

Answer: Y=3, X=5

Step-by-step explanation:

2(2y-1) + 3y=19

4y-2+ 3y=19

7y=21

Y=3

Plug in y in the second equals

X=2(3) -1

X=6-1

X=5

Hope this helps!

8 0

3 years ago

My question got deleted so I'll post these into two separate

Agata [3.3K]

Answer:

see below

Step-by-step explanation:

1 million

1,000,000 seconds * 1 hour/ 3600 seconds * 1 day/ 24 hours * 1 year / 365 days

.031709792 years

Rounding to 3 decimal places

.032 years

50 years * 365 days/ 1 year * 24 hours/ 1 day * 3600 second / 1 hour

1577000000 seconds

46 inches * 1 ft/ 12 inches * 1 mile/5280 ft

0.000726 miles

8 0

4 years ago

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

4 0

3 years ago