The coordinate of point N after the dilation is N' = (-8/3, 8/3)
<h3>Dilation of coordinates</h3>
Dilation is a transformation technique for changing the size of an object using a scale factor.
Given the coordinate of N from the figure as (-4, 4). If this coordinate point is dilated by a factor of 2/3, then the resulting coordinate will be:
N' = (2/3(-4), 2/3(4))
N' = (-8/3, 8/3)
Hence the coordinate of point N after the dilation is N' = (-8/3, 8/3)
Learn more on scale factor here: brainly.com/question/10253650
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Answer:
Step-by-step explanation:
a+b+c=0, a+b=-c,a+c=-b, b+c=-a
(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=
a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=
a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=
a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=
a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=
6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=
2*[3abc-(a^3+b^3+c^3)]=0
so 3abc-(a^3+b^3+c^3)=0
so a^3+b^3+c^3=3abc
Splitting up the interval [0, 6] into 6 subintervals means we have
![[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]](https://tex.z-dn.net/?f=%5B0%2C1%5D%5Ccup%5B1%2C2%5D%5Ccup%5B2%2C3%5D%5Ccup%5Ccdots%5Ccup%5B5%2C6%5D)
and the respective midpoints are
. We can write these sequentially as
where
.
So the integral is approximately
Recall that
so our sum becomes
Answer:
Step-by-step explanation:
(3/8)*(8/11)=(3*8)/(8*11)= 24/88=12/44=6/22=3/11
or you can symplify 8 and get 3/11 right away.
Answer:
About 7% is the anwser i tried 4% and i got it wrong and it said 7 was correct
