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2 years ago

PLEASE HELP QUICK!

Mathematics

2 answers:

pychu [463]2 years ago

6 0

2808.3 inches
(Used the volume formula)

Ket [755]2 years ago

5 0

Answer:

i got 2808 in3 which wasn't on the list and i was extremely confused, i redid the problem multiple times and got the same answer, i used a calculator AND searched of the web, it still gave me the same answer, if those are the only options something might be wrong, the answer should be 2808 in3.

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At a store, toothbrushes cost x dollars and

maksim [4K]

Answer:

Step-by-step explanation:

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3 years ago

Suppose a friend is having difficulty solving -2(q-5) > -3(q+1). Explain how to solve the inequality, showing all the necessa

IgorC [24]

Firstly, use the distributive property of multiplication (A(B + C) = A×B + A×C) on -2(q - 5) and -3(q + 1): $-2q+10>-3q-3$

Next, apply the addition property of equality (whatever you add to one side you have to add the same quantity to the other), and add 3q on both sides: $q+10>-3$

Lastly, apply the subtraction property of equality (whatever you subtract on one side you have to subtract the same amount on the other side), and subtract 10 on both sides. Your final answer will be $q>-13$ 

8 0

3 years ago

Find two integers whose sum is -3 and product is -18

Mariulka [41]

let two integers be x and y

A.T.Q

x+y= -3

or, x= -3-y(i)

and xy= -18

or,(-3-y)y= -18[by(i)]

or,- -3y-y²= -18

or,-y²= -18+3

or, -y²= -15

or, y²=15

therefore y=✓15

from (i)

x= -3-✓15

y=√15

7 0

2 years ago

Read 2 more answers

Which statement is not always true?

Dafna1 [17]

Which statement is not always true?(1) The product of two irrational numbers is irrational.
(2) The product of two rational numbers is rational.
(3) The sum of two rational numbers is rational.
(4) The sum of a rational number and an irrational number is irrational.
The statement that is not always true is the sum of two rational numbers is rational. The answer is number 3.

6 0

3 years ago

Plz help me with this!!!!!!!!

LenaWriter [7]

Answer: √y

Step-by-step explanation:

$\sqrt[6]{y^3}=y^{\frac{3}{6}}=y^{\frac{1}{2}}=\boxed{\sqrt y}$

4 0

3 years ago