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3 years ago

Plz help me with this!!!!!!!!

Mathematics

1 answer:

LenaWriter [7]3 years ago

4 0

Answer: √y

<u>Step-by-step explanation:</u>

$\sqrt[6]{y^3}=y^{\frac{3}{6}}=y^{\frac{1}{2}}=\boxed{\sqrt y}$

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Evaluate (solve) the power: 2^9

german

Answer:

The corrext answer is, 512.

3 0

3 years ago

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3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

7 0

3 years ago

April had

Bumek [7]

First thing First. You must find have a common denominator. If you want to find it then you do this

3: 3 6 9 12 15 18 21
7: 7 14 21 28

Once you found a number they have in common (21) You do this next

3/7 * 3/3 = 9/21
2/3 * 7/7 = 14/21

Now the next thing you do is subtract your numerators but not the denominators

14-9=5

5/12

you cant simplified so your done! Hope this helps!!!! <span />

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3 years ago

you roll a six sided number cube and flip a coin what is the probability of rolling a number greater than 5 and flipping heads?

Whitepunk [10]

Answer:

0.08333... or 8.333...%

Step-by-step explanation:

1/6 * 1/2 = 1/12

5 0

2 years ago

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How manys days makes a leap year?

dem82 [27]

Answer: In an ordinary year, if you were to count all the days in a calendar from January to December, you'd count 365 days. But approximately every four years, February has 29 days instead of 28. So, there are 366 days in the year. This is called a leap year.

Step-by-step explanation:

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3 years ago