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Mamont248 [21]
3 years ago
5

Plz help me with this!!!!!!!!

Mathematics
1 answer:
LenaWriter [7]3 years ago
4 0

Answer:  √y  

<u>Step-by-step explanation:</u>

\sqrt[6]{y^3}=y^{\frac{3}{6}}=y^{\frac{1}{2}}=\boxed{\sqrt y}

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What is the maximum area for a rectangle whose perimeter is 48 meters?
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Answer:

12m²

Step-by-step explanation:

For a rectangle, with length L and width W,

the perimeter is given as

Perimeter,

P = (2 x Length)  + (2 x Width)

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It is given that the perimeter is 48, hence

48 = 2L + 2W   (divide both sides by 2)

24 = L + W

or

L = 24 - W -----> eq 1

Also realize that the Area of a Rectangle is given by

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Substituting eq 1 into eq 2,

A = (24 - W) x W

A = -W² + 24W

Recall that for a quadratic equation y = ax² + bx + c, the maxima or minima is given by y(max) =  -b/2a

In this case, b = 24 and a = -1

-b/2a = -24/[ 2(-1) ] = 12

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3 years ago
Geometry
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And so your circumference is 8\pi

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Alyssa took a math test with 20 questions and she answered 16 questions correctly. In order get an A, she needs to answer at lea
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