Find answer is the given attachment
X+(x+2)+(x+4)=396, x+x+x+6=396, 3x+6=396, 3x=396-6, 3x=390, x=130, x+2=130+2=132, x+4=130+4=134. The three consecutive even integers are 130, 132, 134
It's prime because the constant term is positive and there is no middle term. If it were x^2 - 16, we could use (x+4)(x-4), but because 16 is positive, it cannot be factored
Answer:
C) x = -
2 ± 2
7
3
Step-by-step explanation:
If log2 (x-3) =1
It means that:
2^1 = x-3
2=x-3 |+3 to both sides
2+3=x
x=5
