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Answer:
m - 3000
b - 2000
please correct me if i am wrong.
Step-by-step explanation:
You can use the change of base formula to get

and also

In general, the change of base formula is

Answer:

Step-by-step explanation:
We want to model the position of the submarine as a function of time.
Notice that we have a constant amount. The initial depth: 750 meters
Then we have a factor that varies over time. Every hour the submarine ascends 50 meters. therefore as t increases the depth y(t) of the submarine decreases. Then the factor is:
-50t.
Where t represents the time in hours.
Then the equation that represents the new position of the submarine in relation to the level of the sea:
