Answer:
Here is the ans...hope it helps:)
I think it’s the third one if not I apologize
Answer:
Step-by-step explanation:
We could invent set B: {-2, 1, 3, 5, 6, 10} and then correctly state tht set A is a subset of B, because {-2, 1, 3} is also found in A.
This is the theory of algebra, to simply the expression we proceed as follows;
[sqrt(x-2)+5/sqrt(x-2)]/(x-2)
simplifying the numerator we get:
sqrt(x-2)+5/sqrt(x-2)
=[x-2+5]/sqrt(x-2)
=(x+3)/sqrt(x-2)
therefore our entire expression will be:
[(x+3)/sqrt(x-2)]/(x-2)
[(x+3)/(x-2)^(1/2)]*1/(x-2)
applying the law if indices we get
=(x+3)/(x-2)^(3/2)
First operation is to subtract
2x +5 = 10
2x +5 (-5) = 10 (-5)
2x = 5
Second operation is to divide
2x/2 = 5/2
x = 5/2
hope this helps :D