Answer:
The correct option is : cells containing empty plasmid vectors
Explanation:
The blue-white screen is a technique which involves the rapid identification of the recombinant bacteria in a vector-based molecular cloning experiment. In this method, a DNA ligated vector is inserted in a host cell which is viable for transformation and grown in presence of X-gal.
The cells that are transformed with the vectors having the recombinant DNA produce the white colonies. Whereas, the cells transformed with empty vector i.e. the non-recombinant plasmids, produce the blue colonies.
Answer:
Acetyl-Coa + 3 NAD + + Q + GDP + Pi + 2H2O >
CoA-SH + 3 NADH + 3 H + + QH2 + GTP + 2 CO2
Explanation:
The separation of the sister chromatids during the cell division occurs in the anaphase in mitosis and anaphase II in meiosis.
During the anaphase in mitosis, and the anaphase II of the meiosis, the chromosomes aligned at the center of the nucleus separates and the sister chromatids of the chromosomes starts moving towards the opposite poles as the spindle fibers starts contracting.
Answer:
chemical reaction:-
12H20 + 6CO2 + light =====> C6H12O6 + 6H2O + 6O2
the above reaction shows that if we combine water,carbon dioxide and sunlight ,the resultant products will be glucose ,water and oxygen .
The plant converts the carbon dioxide into energy and oxygen by different steps that include
- absorption of light
- conversion of NADP into NADPH+
- conversion of ADP into ATP
- formation of carbohydrates from CO2 !
I believe b. Let me know if it's wrong
