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zvonat [6]
3 years ago
5

A school principal wants to know more about the number of students absent each day. He counts the number of students absent each

day for one week: {24, 18, 31,
Mathematics
1 answer:
True [87]3 years ago
6 0

Answer:

6.27

Step-by-step explanation:

We are to obtain the standard deviation of the given values :

{24, 18, 31,25, 34}

The standard deviation = √(Σ(x - mean)²/ n)

The mean = (ΣX) /n

Using calculator to save computation time :

The standard deviation, s = 6.27 (2 decimal places)

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Youre amazing!!! could you help me? 50 points!!! Write an expression that can be used to produce vector d from vector c, and exp
andrew-mc [135]

Answer:

Multiply vector c by the scalar -1/2.

Step-by-step explanation:

Look at vector c.

It has an x component of 4 and a y component of 4.

You can write vector c as a sum of its components using unit vectors in the x direction (i) and in the y direction (j).

c = 4i + 4j

Now look at vector d, and write it also as a sum of its x and y components.

d = -2i - 2j

Now ask yourself, what operation do I do to 4 to end up with -2?

One answer is to multiply 4 by -1/2.

d = (-1/2)c = (-1/2)(4i) + (-1/2)(4j) = -2i - 2j

That worked. By multiplying vector c by the scalar -1/2, you end up with vector d.

8 0
2 years ago
What is the simplified form of left parenthesis 27 x to the power of negative six end power y to the power of 12 end power right
Tanzania [10]
Hello,
Please, see the attached file,
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5 0
2 years ago
ASAP—-what is the missing value
olga_2 [115]

Answer:

im sure its 139

Step-by-step explanation:

because you do 128 + 93 which is 221

next, you do 360 (triangle angles) then you do 360-221

which gives you 139!

hope it helped! =)

8 0
3 years ago
How do you write 3 ones as a decimal
harina [27]
3.0, because the 3 is in the ones place.
4 0
3 years ago
Read 2 more answers
the graph of y=e^tanx-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point? I g
Svetlanka [38]
Y = e^tanx   -   2

To find at which point it crosses x axis we state that y= 0

e^tanx   - 2 = 0 
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tanx = ln 2
tanx = 0.69314
x = 0.6061

to find slope at that point first we need to find first derivative of funtion y.

y' = (e^tanx)*1/cos^2(x)

now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
3 0
2 years ago
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