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3 years ago

Simplify 12edf – 13def. State a property that you can use.

Mathematics

1 answer:

Anna [14]3 years ago

5 0

Answer:

-def. In multiplication, the order doesn't matter.

Step-by-step explanation:

A crucial property you can use to simplify this is the fact that, in multiplication, order doesn't matter.

3 * 2 = 6

2 * 3 = 6

5 * 2 * 3 = 30

2 * 3 * 5 = 30

3 * 2 * 5 = 30

Thus,

edf, or

e * d * f

is the same as def,

d * e * f

e * d * f = d * e * f

edf = def

Thus, 12edf is the same as 12def. We can put this in our expression:

12edf - 13def

12def - 13def

Now, we can see that this will equal -1def or -def

12def - 13def

-1def

-def

Answer: -def. In multiplication, the order doesn't matter.

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What is the solution to the equation below? Round your answer to two decimal places. log5 x=2.1

Natali5045456 [20]

Answer:

D. x=29.37

Step-by-step explanation:

To answer this question you have to understand how log work. Log is the abbreviation of logarithm and it works as an inverse function of exponentiation.

The rules should be like this:

$log_{a} b = c\\a^{c} = b\\$

Variable a in the equation is called base. If it left empty you can assume its base 10. The log in this question using 5 as a base. Variable b will be x and variable c will be 2.1

Now, let's change the variable of the equation using the information from the question.

$log_{a} b = c\\\log_{5} x = 2.1\\5^{2.1} = x\\x= log_5}^{-1}2.1\\x=29.365473577\\x=29.37$

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3 years ago

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mestny [16]

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3 years ago

Read 2 more answers

The arithmetic sequence a_ia i a, start subscript, i, end subscript is defined by the formula: a_1 = 15a 1 =15a, start subsc

daser333 [38]

Answer:

-1,512,390

Step-by-step explanation:

Given

a1 = 15

$a_i = a_{i-1} -7$

Let us generate the first three terms of the sequence

$a_2 = a_{2-1}-7\\a_2 = a_1 - 7\\a_2 = 15-7\\a_2 = 8$

For $a_3$

$a_3 = a_{3-1}-7\\a_3 = a_2 - 7\\a_3 = 8-7\\a_3 = 1$

Hence the first three terms ae 15, 8, 1...

This sequence forms an arithmetic progression with;

first term a = 15

common difference d = 8 - 15 = - -8 = -7

n is the number of terms = 660 (since we are looking for the sum of the first 660 terms)

Using the formula;

$S_n = \frac{n}{2}[2a + (n-1)d]\\$

Substitute the given values;

$S_{660} = \frac{660}{2}[2(15) + (660-1)(-7)]\\S_{660} = 330[30 + (659)(-7)]\\S_{660} = 330[30 -4613]\\S_{660} = 330[-4583]\\S_{660} = -1,512,390$

Hence the sum of the first 660 terms of the sequence is -1,512,390

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3 years ago

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Anna35 [415]

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3 years ago

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leonid [27]

Answer:

Step-by-step explanation:

1.2x = 24

x = 20

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3 years ago