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kakasveta [241]
3 years ago
5

One of the angles formed by two intersecting lines measures 30°. What are the measures of the other three angles? i need help AS

AP
Mathematics
1 answer:
lord [1]3 years ago
4 0

Answer: The angles are 30 30, 150, 150

Step-by-step explanation: Two lines intersect means they cross. According to the vertical angle theorem, angles that are across are the same, a line is 180 degrees so it means the angles that make up the supplementary pair add up to 180(180-30=150). So there are 2 150 degree angles and 2 30 degree angles

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The teacher separated her class of 28 students into 2 groups. One group had 4 more than twice as many students as the other grou
hodyreva [135]
One group has 12 the other has 16
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"Round 2 significant figures<br><br> 5,239"<br><br> what does it want me to do here?
olasank [31]

Answer:

5,200

Step-by-step explanation:

Significant figure = digit number

they want you to change 5239 to 2 s.f

thus,5200 <--2 digit number

6 0
4 years ago
Find the value of XP if X is between P and Q. <br><br> XQ= 3k, XP= 7k - 2, PQ= 6k + 18
VMariaS [17]

If X is between P and Q, then PQ is the whole line segment and XQ and XP are line segments that add up to PQ. Therefore, you can make an equation where XQ and XP add up to PQ.

XQ + XP = PQ

(3k) + (7k - 2) = 6k + 18

Combine like terms.

10k - 2 = 6k + 18

Add 2 to both sides.

10k = 6k + 20

Subtract 6k from both sides.

4k = 20

Divide both sides by 4.

k = 5

Plug 5 for k into XP.

XP = 7(5) - 2 ⇒ 35 - 2

XP = 33

5 0
3 years ago
Read 2 more answers
If g(x)=4x2-16 were shifter 5 units to the right and 2 down, what would the new equation be?
Tatiana [17]
G(x)=4x^2-16

To shift to the right we have to subtract from the value of x, in this case by 5 units...

h(x)=4(x-5)^2-16

h(x)=4(x^2-10x+25)-16

h(x)=4x^2-40x+100-16

h(x)=4x^2-40x+84

Now to shift the function downwards by 2 units we must subtract the constant 2 from h(x)

h(x)=4x^2-40x+84-2

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6 0
3 years ago
Please answer quickly!!!
mixas84 [53]

Answer:

Step-by-step explanation:

5x + 13y = 232

12x + 7y = 218

For each choice:

a) The first equation can be multiplied by –13 and the second equation by 7 to eliminate y. So we have

- 65x - 169y = - 3016

84x + 49y = 1526

Can not eliminate x and y.

b) The first equation can be multiplied by 7 and the second equation by 13 to eliminate y. So we have

35x  + 91 y = 1624

156x + 91y = 2834

Can not eliminate x and y if we ADD.

<em>(If we subtract, this is Yes)</em>

<em></em>

c) The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.

-60x - 156y = - 2784

60x + 35y = 1090

The answer is YES

d) The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.

25x + 65y = 1160

144x + 84y = 2616

Can not eliminate x and y

The final answer is C

3 0
4 years ago
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