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serg [7]
2 years ago
12

Two students, Tony and Mike, factored the trinomial 8x2 − 12x − 8. Tony factored it as 4(x − 2)(2x + 1) and Mike factored it as

(x − 2)(8x + 4). Indicate which student factored the trinomial completely and which student did not, and explain why. (10 points)
Mathematics
1 answer:
vlada-n [284]2 years ago
8 0

Tony and Mike, factored the trinomial 8x^2 - 12x - 8

Tony factored it as 4(x - 2)(2x + 1) and

Mike factored it as (x - 2)(8x + 4)

8x^2 - 12x - 8

GCF is 4. We factor out 4

4(2x^2 - 3x - 2)

2*-2=-4. We find out two factors whose product is -4  and sum is -3

two factors are -4  and 1. Split middle term -3x using two factors

4(2x^2 - 4x + 1x - 2)

Group first two terms and last two terms

4[(2x^2 - 4x) + (1x - 2)]

Factor out GCF from each group

4[2x(x - 2) + 1(x - 2)

4(2x+1)(x-2)

Tony factored it correctly

Mike factored it as (x − 2)(8x + 4)

Mike factor 8x+4 further. GCF of 8 and 4 is 4

So it becomes 4(2x+1)

Mike not factored it completely




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Solve for x : log(3x) + log(x + 4) = log(15).<br><br>Please explain it to me.​
zlopas [31]

Answer:

x = 1

Explanation:

\sf \rightarrow log(3x) + log(x + 4) = log(15)

Rule: log(a) + log(b) = log(ab)

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\sf \rightarrow x = 1,  \ x = -5

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