Tony and Mike, factored the trinomial ![8x^2 - 12x - 8](https://tex.z-dn.net/?f=8x%5E2%20-%2012x%20-%208)
Tony factored it as 4(x - 2)(2x + 1) and
Mike factored it as (x - 2)(8x + 4)
![8x^2 - 12x - 8](https://tex.z-dn.net/?f=8x%5E2%20-%2012x%20-%208)
GCF is 4. We factor out 4
![4(2x^2 - 3x - 2)](https://tex.z-dn.net/?f=4%282x%5E2%20-%203x%20-%202%29)
2*-2=-4. We find out two factors whose product is -4 and sum is -3
two factors are -4 and 1. Split middle term -3x using two factors
![4(2x^2 - 4x + 1x - 2)](https://tex.z-dn.net/?f=4%282x%5E2%20-%204x%20%2B%201x%20-%202%29)
Group first two terms and last two terms
![4[(2x^2 - 4x) + (1x - 2)]](https://tex.z-dn.net/?f=4%5B%282x%5E2%20-%204x%29%20%2B%20%281x%20-%202%29%5D)
Factor out GCF from each group
![4[2x(x - 2) + 1(x - 2)](https://tex.z-dn.net/?f=4%5B2x%28x%20-%202%29%20%2B%201%28x%20-%202%29)
4(2x+1)(x-2)
Tony factored it correctly
Mike factored it as (x − 2)(8x + 4)
Mike factor 8x+4 further. GCF of 8 and 4 is 4
So it becomes 4(2x+1)
Mike not factored it completely