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Julli [10]
3 years ago
9

A​ 12-sided solid has faces numbered 1 to 12. The table shows the results of rolling the solid 200 times. Find the experimental

probability of rolling a number less than 3.

Mathematics
2 answers:
aksik [14]3 years ago
5 0
The answer is 17%.. I think
Georgia [21]3 years ago
3 0
The probability is about 17%
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The vertex formation of a parabola is x = 8(y- 1)2-76.
Gennadij [26K]

Answer:

\boxed{x=8y^2-16y-68}

Step-by-step explanation:

Hello, please consider the following.

x=8(y- 1)^2-76\\\\x=8(y^2-2y+1)-76\\\\x=8y^2-16y+8-76\\\\\boxed{x=8y^2-16y-68}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0
3 years ago
Read 2 more answers
Quadrilateral ABCD is inscribed in a circle. What is the measure of angle A?
Anvisha [2.4K]
Angle A measures to 59 degrees.
5 0
3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
Simplify (write without the absolute value sign): |x−(−12)|, if x&lt;−12
VladimirAG [237]

Answer:

|x + 12|

Step-by-step explanation:

The question I took form you I assume looks like this...

|x - (-12)|

Therefore, if we simplify this, the answer is |x + 12|

This is the answer because you would multiply -1 by -12

3 0
3 years ago
Using the model of 7.77, how does the 7 in the tenths place compare to the 7 in the place to its left?
igomit [66]
It is 10 times smaller
8 0
3 years ago
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