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gulaghasi [49]
3 years ago
14

Solve the formula -4x+y= -6 for x.

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
5 0

Answer:

x = 3/2 + y/4

Step-by-step explanation:

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?????? I don’t get it
QveST [7]

Answer:

His gain was greater on the first play because if you convert 2 yards to feet you get 6ft and 6 feet is greater than 5 feet which means the football player had a greater gain on the first play.

Step-by-step explanation:

1 yard is 3 ft

2yards x 3=6 ft

6ft> 5ft

first play> Second play

7 0
2 years ago
Read 2 more answers
PLEASE HELP!! FAST :)
chubhunter [2.5K]
Since x³ = x^(1/3) you can say that

(x
¹⁰)^(1/3) = x^10/3 = x^(3 + 1/3) = 

x³ ·∛x
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3 years ago
Use compatible numbers to estimate the quotient 63.5÷5
Leto [7]
63.5 divided by 5 is 12.7.      
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3 years ago
Things on sale at 25% off the original price which expression represents the sale price of the original price of the jeans is 40
olya-2409 [2.1K]
What is the question
8 0
3 years ago
(question 4 only plz)
Hatshy [7]
#4
White block(s) = 2
Red block(s) = 1
Purple block(s) = 3
Total = 2 +1 + 3 = 6 blocks

a) P(white) = \frac{2}{6} = \frac{1}{3}
    P(red) = \frac{1}{6}
    P(purple) = \frac{3}{6} =  \frac{1}{2}

b)Not white block:
   1 - \frac{1}{3}   OR   \frac{1}{2} + \frac{1}{6}
    \frac{2}{3}                 \frac{2}{3}
Because, when they say no white blocks, we simply do not count them and add the rest to find that probability without white blocks.

c) The probability stays the same: lets say now we have
4 white blocks, 2 red, and 6 purple, total will be 12

P(white)=\frac{4}{12} which is still \frac{1}{3}

d) We get two more blocks in the numerator: lets say we have 4 white blocks, 3 red, 5 purple (after adding 2 of each color), total will be 12

P(purple)=\frac{5}{12}
(im not quite sure if my explanation here helps you though)

e) 1 more of white and purple, 5 more of red
  white = 3, purple = 4, red = 6, total = 12
(you can either add 2 to white or purple but make sure you add 5 of red)

P(red)=\frac{6}{12} = \frac{1}{2}
  


5 0
3 years ago
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