Martin will have to mark 0.125 on the
Let the original weight of the scale be 1kg. Hence we can say the original mark for 1kg weight is 1 that is:
1kg = 1 ................ 1
Since we are to calculate where to mark for a 1/8 kg weight, we can write;
1/8 kg = x ..................2
Divide both expressions
This means Martin will have to mark 0.125 on the scale.
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Answer:
The required graph is shown below:
Step-by-step explanation:
Consider the provided graph 
The above function is a linear function.
We can draw the graph of the linear function with the help of two points.
Substitute x = 0 in
Hence, the coordinates are (0,2)
Substitute f(x) = 0 in
Hence, the coordinates are (-0.0625,0)
Now join the above points.
The required graph is shown below:
Please, group your sets of numbers, using { } notation or at least semicolons ( ; ). Thanks.
Looking at what I think is your first set: { sqrt(4), sqrt(5), sqrt(16) }
Square each of these and then subst. the results into the Pythagorean Theorem:
{ 4, 5, 16 } Do 4 and 5 when added together result in 16? NO.
Therefore, { sqrt(4), sqrt(5), sqrt(16) } does not produce a right triangle.
Your turn. Pick out the next 3 numbers and test them using the Pyth. Thm.
Answer:
c = -2
On a graph the intersecting point would be at (-2, -10)
Step-by-step explanation:
Answer:
Yes they can all be written in y = mx + b. You just have to move the terms around.
Step-by-step explanation:
y = 2x -3, this is already in slope-intercept form
Now, y - 2 = x + 2: We can add 2 on both sides to cancel out the one on the left side:
y - 2 = x + 2
y - 2 + 2 = x + + 2
y = x + 4 <-- This is in y = mx + b form
Now the last one, 3x = 9 + 3y
We can first divide all terms by 3,
3x = 9 + 3y
/3 /3 /3
x = 3 + y: Then we can subtract 3 from both sides:
x - 3 = 3 + y - 3
x - 3 = y
These are all linear equations because none of the x's have bigger powers than 1. x^2 is a quadratic equation and x^3 is cubic equation.
