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3 years ago

A triangular field has sides of 218.5 m and 224.5 m, and the angle between them measures 58.20 . Find the area of the field.

Mathematics

1 answer:

telo118 [61]3 years ago

5 0

Answer:

20,845 square meters

Step-by-step explanation:

We can use the formula for area of a triangle to figure this out easily.

Area = $\frac{1}{2}abSinC$

Where

a and b are the two side lengths of the triangle given, and

C is the ANGLE BETWEEN the two sides

Clearly, we see that one side is 218.5 and other is 224.5 and the angle between them is given by 58.2 degrees. Now we simply substitute these values into the formula and get the area:

$A=\frac{1}{2}abSinC\\A=\frac{1}{2}(218.5)(224.5)Sin(58.2)\\A=20,844.99$

Rounding, we get the area to be 20,845 square meters

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Answer:

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Step-by-step explanation:

Given diameter of the racquetballs (x)= 4 cm

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Δ C(x)/ Δ x = C'(x).

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Answer:

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Answer:

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