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olga_2 [115]
2 years ago
7

What is the perimeter of the polygon below?

Mathematics
1 answer:
8090 [49]2 years ago
7 0
The answer to that is 20.5
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Please may someone help with c
german

Step-by-step explanation:

Distance between two villages = d

(a) \:  \frac{4}{5}  \: of \: d =  \frac{4}{5} d \\  \\ (b) \:  \frac{3}{4}  \: of \: d =  \frac{3}{4} d  \\  \\ (c) \: \frac{4}{5} d -   \frac{3}{4} d = 1.5 \\  \\  \therefore \:   \bigg(\frac{4}{5} -   \frac{3}{4} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{4 \times 4 - 3 \times 5}{5 \times 4} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{16- 15}{20} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{1}{20} \bigg) d = 1.5 \\  \\ \therefore \: d = 1.5 \times 20 \\  \\ \:  \:  \:  \:  \:  \huge \orange{ \boxed{{ \therefore \: d = 30}}}

4 0
4 years ago
Factorise FULLY and show working out (3)
olchik [2.2K]
48-3x^2=-3(x^2-16)=-3(x-4)(x+4)
4 0
3 years ago
What value of m makes this equation true?
iris [78.8K]
The correct answer is B) m=-8

First, add 9 on both sides of the equation. You should end up with 4m=-32.

Next, divide both sides of the equation by 4. You should end up with m=-8. (A negative divided by a positive equals a negative)

Hope this helps! Have a great day ;)
6 0
3 years ago
Please help.........
faust18 [17]
The answer for PA is 60/13. This is found by
The area of the rectangle is 60, therefore, the big triangle areas are 30 each. We know that the hypotenuse is 13, so therefore, we get
1/2(13*PA) = 30. This then simplifies to 
13 * PA = 60, which then turns into 
PA = 60/13.

Hope this helps and have a nice day:)
5 0
4 years ago
Use the graph to find the bear’s average heart rate when it’s active and when it hibernating
lorasvet [3.4K]

we know that

the rate of a linear equation  is equal to the slope

Step 1

Find the  bear’s average heart rate when it’s active

Let

A(1.5,90)   B ( 2,120)

the slope is equal to

m=(y2-y1)/(x2-x1)

m=(120-90)/(2-1.5)=30/0.5

m=60 heartbeats/min

therefore

the answer part a) is

the bear’s average heart rate when it’s active is 60 heartbeats/min

Step 2

Find the  bear’s average heart rate when it’s hibernating

Let

A(1.5,18)   B ( 2,24)

the slope is equal to

m=(y2-y1)/(x2-x1)

m=(24-18)/(2-1.5)=6/0.5

m=12 heartbeats/min

therefore

the answer part b) is

the bear’s average heart rate when it’s hibernating is 12 heartbeats/min


7 0
3 years ago
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