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3 years ago

Write an integer to represent this situation: A boat is sitting at sea level.

Mathematics

1 answer:

Bezzdna [24]3 years ago

8 0

Answer:

0 because 0 is sea level, anything below is negative and anything above is positive.

Step-by-step explanation:

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Combine like terms to simplify the expression:<br> 1.17-0.07a+(-3.92a)

Pachacha [2.7K]

After combining like terms and simplifying $1.17-0.07a+(-3.92a)$ we get $1.17-3.99a$

Step-by-step explanation:

We need to combine like terms to simplify the expression:

$1.17-0.07a+(-3.92a)$

Like terms: The terms are like when they have same variable and same exponent.

Solving:

$1.17-0.07a+(-3.92a)\\=1.17-0.07a-3.92a\\=1.17+(-0.07a-3.92a)\\=1.17+(-3.99a)\\=1.17-3.99a$

So, After combining like terms and simplifying $1.17-0.07a+(-3.92a)$ we get $1.17-3.99a$

Keywords: Solving Expressions

Learn more about Solving Expressions at:

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3 0

3 years ago

What is 4-2y+(-8y)+6.2 simplified

S_A_V [24]

Answer:

- 10 y+10.2

Step-by-step explanation:

4-2y+(-8y)+6.2

combine like terms

-2y -8y +4+6.2

- 10 y+10.2

3 0

4 years ago

Read 2 more answers

A photocopier costs $25 000. Its unit cost depreciation is calculated at $0.01 per page. The equation to determine its value aft

Drupady [299]

.......................

5 0

3 years ago

Kayla's age is 3 less than twive her brother's age. Kayla is 13 years old. How old is her brother?

Kamila [148]

Answer: 6

Step-by-step explanation:

3 times 2

7 0

4 years ago

The U.S. Fish and Wildlife Service reported that the mean length of six-year-old rainbow trout in the Arolik River in Alaska is

Anettt [7]

Answer:

The size limit for 15% of of six-year-old trout is 438.52 mm.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 481 millimeters

Standard Deviation, σ = 41 millimeters

We are given that the distribution of mean length of six-year-old rainbow trout is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.15

$P( X < x) = P( z < \displaystyle\frac{x - 481}{41})=0.15$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 481}{41} = -1.036\\\\x = 438.524$

Thus, the size limit for 15% of of six-year-old trout is 438.52 mm.

5 0

3 years ago